數字轉換爲Word C++

Question

#include <iostream> //including header files#include <string> 
#include <string> 

using namespace std; 


//string array declared 
string units[3][11] = {{"One","Two","Three", "Four", "Five", "Six","Seven","Eight", "Nine","Ten"}, 
{"Eleven", "Twelve", "Thirteen","Fourteen", "Fifteen", "Sixteen", "Seventeen","Eighteen", "Nineteen"}, 
{"Twenty", "Thirty", "Fourty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety", "", ""}}; 


//function defs 
void func6 (int unsigned long i); 
void func5 (int unsigned long i); 
void func4 (int unsigned i); 
void func3 (int unsigned i); 
void func2 (int unsigned i); 
void func1 (int unsigned t); 
void func (int unsigned i); 

int main() //main body of fcn 
{ 
long int num; //declaring integers 

int j=1; 

while (j==1) //start of while loop 
    { 
     cout << "Enter a number between -2 billion and 2 billion " << endl; //prompts user for i/p and stores it 
     cin >> num; 

     if ((num < -2000000000) || (num > 2000000000)) //exits program if not within these limits 
     { 
      cout << "Number Invalid " << endl; 
      return 0; 
     } 
     else 
     { 
      func(num); //call functions 
      func1(num); 
      func2(num); 
      func3(num); 
      func4(num); 
      func5(num); 
//   func6(num); 
     } 
    } 
} 


/*void func6 (int unsigned long i) //start of fcn5 
{ 
    int unsigned long t; //declares integer t 


    if (i>9999&&i<100000) //if within these limits statement executes 
    { 
     t=i%1000; //works out remainder 
     i=i/1000; //works out new i value 
     cout << units[1][i-11] << " Thousand "; //prints out result whilst looking up table 


     if (t<10) //if remainder within limits calls function 
     func(t); 
     else if (t>=10&&t<20) 
     func1(t); 
     else if (t>19&&t<=100) 
     func2(t); 
     else if (t>99&&t<1000) 
     func3(t); 


    } 
} 
*/ 



void func5 (int unsigned long i) //start of fcn5 
{ 
    int unsigned long t; //declaring integer 
    if (i>9999&&i<100000) // if value within these limits then execute 
    { 
     t=i%10000; //works out remainder 
     i=i/10000; //works out new value of i 
     cout << units[2][i-2] << " Thousand "; //prints out result whilst looking up table 

     if (t<10) //calls function if remainder within these limits 
     func(t); 
     else if (t>=10&&t<20) 
     func1(t); 
     else if (t>=20&&t<100) 
     func2(t); 
     else if (t>=100&&t<1000) 
     func3(t); 

    } 
} 



void func4 (int unsigned i) //start of function 4 
{ 
    int unsigned t; //declares integer 
    if (i>=1000&&i<10000) //if within these limits execute fcn 
    { 
     t=i%1000; //works out remainder 
     i=i/1000; //works out new value of i 
     cout << units[0][i-1] << " Thousand "; //prints out result whilst looking up table 

     if (t<10) //calls function if remainder within limits 
     func(t); 
     else if (t>=10&&t<20) 
     func1(t); 
     else if (t>=20&&t<100) 
     func2(t); 
     else if (t>=100&&t<1000) 
     func3(t); 


    } 
} 


void func3 (int unsigned i) //start of fcn 3 
{ 
    int unsigned t; //delcares integer 
    if (i>=100&&i<1000) //statement executes if within limits 
    { 
     t=i%100; //works out remainder 
     i=i/100; //works out new value 
     cout << units[0][i-1] << " Hundred "; //prints out result whilst looking up table 

     if (t<10) //if remainder within these limits calls previous functions 
     func(t); 
     else if (t>=10&&t<20) 
     func1(t); 
     else if (t>=20&&t<100) 
     func2(t); 
    } 
} 


void func2(int unsigned i) //start of fcn2 
{ 
    int unsigned t; //declares integer 


    if (i>=20&&i<100) //if i within limits statement executes 
    { 
      t=i%10; //works out remainder 
      i=i/10; //works out new i value 
      cout << units[2][i-2] ; //prints result out whilst looking up table 


      if (t < 10) //if remainder within these limits calls function 
      func(t); 
    } 
} 


void func1(int unsigned i) //start of func1 
{ 
    int unsigned t; //declares integer 
    if (i>10&&i<20) //if i within these limits statement executes 
    { 
     t=i%10; //works out remainder 
     cout << units[1][t-1] << endl; //prints out value whilst looking up table 
    } 
} 


void func(int unsigned t) //start of fcn 
{ 
    if (t<=10) //if statement less than 10 executes 
    { 
     cout << " " << units[0][t-1] << endl; //prints out result whilst looking up table. 
    } 
} 

右我已經寫了這個代碼，它適用於大多數的數字卻落下了混亂，同時試圖打印出10000，11000，12000，90000 ...，91000等。它的東西與餘下的和我的價值做。我無法弄清楚整天干什麼。有任何想法嗎？現在，當我輸入一個數字時，它會返回它，但然後崩潰。

Answer 1

原帖是可怕的。抱歉。 現在，我正確地閱讀了您的問題，我可以給你一些初步的版本。但你必須稍微修改它才能調整它。

string bases[6] = {"", "ten", "hundred", "thousand", "ten thousand", "million"}; 


string digit_to_word (int n) 
{ 
if(n == 1) 
    return "one"; 
if(n == 2) 
    return "two"; 
if(n == 3) 
    return "three"; 
if(n == 4) 
    return "four"; 

} 

string number_to_word(int i, int pow) { 
    if(i < 10) { 
     return digit_to_word(i); 
    } 

    else { 
     int k = i/10; 
     if(k > 10) 
     return number_to_word(k, ++pow) + "^" + bases[pow] + " " + digit_to_word(i%10) ; 
     else 
     return digit_to_word(k) + "^" + bases[pow] + " " + " " + digit_to_word(i%10); 
    } 
} 



int main() { 
    cin>>i; 
    cout << number_to_word(i, 1); 
    return 0; 
} 

Answer 2

這不是一個循環，這是遞歸

假設你有123,456,789，然後用你的代碼你上面有

億= 0 百萬= 123個 數千= 456

現在你想要輸出「一二三百四十五萬六千......」，所以你需要將123轉換爲「一百二十三」，你需要將456轉換爲「四百一五十六「。你是怎樣做的？那麼它就是你已經試圖解決的問題，只有更小的數字。

所以你是對的，你確實需要編寫一個函數，當這個函數需要將百萬字節轉換成單詞時，它會自動調用它（即它將是遞歸的）。當它轉換成千上萬時相同。