當我搜索帶有數字的字母顯示錯誤？

Question

mysql_connect("localhost", "root", "") or die(mysql_error()); 
    mysql_select_db("corporate_personnel_order_for_2016") or die(mysql_error()); 
    $search = $_GET['search']; 
    $result = mysql_query("SELECT * FROM obs WHERE OBS_NUMBER LIKE $search;") or die(mysql_error()); 
echo "<table><tr><th width=250>OBS Number</th><th width=250>Name</th><th width=250>Purpose</th><th width=250>Date of OB</th><th width=250>Destination</th></tr>"; 



while ($row = mysql_fetch_array($result)) { 
    echo '<table><tr>'; 
    echo '<td width=250>' . $row['OBS_NUMBER'] . '</td>'; 
    echo '<td width=250>' . $row['NAME'] . '</td>'; 
    echo '<td width=250>' . $row['PURPOSE'] . '</td>'; 
    echo '<td width=250>' . $row['DATE_OF_OB'] . '</td>'; 
    echo '<td width=250>' . $row['DESTINATION'] . '</td>'; 
    echo '</tr>'; 
echo "</table>"; 

當我搜索一個字母和數字的條目它不能顯示一個錯誤，但是當我搜索一個數字只顯示在我的表？

Answer 1

試試這個

$result = mysql_query("SELECT * FROM obs WHERE OBS_NUMBER LIKE '".$search."'") or die(mysql_error()); 

或本

$result = mysql_query("SELECT * FROM obs WHERE OBS_NUMBER LIKE '%".$search."%'") or die(mysql_error());