無法使用Java發送帖子表格

Question

代碼的目標是將參數插入到表單中，然後提交表單，然後將表單輸入到MySQL數據庫中。問題是該方法不會發布數據。我不確定我做錯了什麼，我已經看過這麼多的問題，但似乎沒有任何工作。

這裏是表格。

<form action="http://localhost/Documents/dataadded.php" method="post"> 

<b>Add a New Data</b> 

<p>Email Address: 
<input type="text" name="email_address" size="30" value="" /> 
</p> 

<p>Email Pass: 
<input type="text" name="email_pass" size="30" value="" /> 
</p> 

<p> 
<input type="submit" name="submit" value="Send" /> 
</p> 

</form> 

這是Java代碼。

public static void main(String[] args) { 


    String key1 = "email_address"; 
    String key2 = "email_pass"; 
    String key3 = "submit"; 

    String param1 = "testemail@gmail.com"; 
    String param2 = "password123"; 
    String param3 = "Send"; 
    try { 
     URL website = new URL("http://localhost/Documents/added.php"); 

     Map<String,String> arguments = new LinkedHashMap<>(); 
     arguments.put(key1, param1); 
     arguments.put(key2, param2); 
     arguments.put(key3, param3); 

     StringJoiner sj = new StringJoiner("&"); 
     for(Map.Entry<String,String> entry : arguments.entrySet()) 
      sj.add(URLEncoder.encode(entry.getKey(), "UTF-8") + "=" 
       + URLEncoder.encode(entry.getValue(), "UTF-8")); 
     byte[] out = sj.toString().getBytes(StandardCharsets.UTF_8); 
     int length = out.length; 

     HttpURLConnection connection = (HttpURLConnection) website.openConnection(); 
     connection.setRequestMethod("POST"); 
     connection.setFixedLengthStreamingMode(length); 
     connection.setRequestProperty("Content-Type", "application/x-www-form-urlencoded; charset=UTF-8"); 
     connection.setDoOutput(true); 
     connection.getOutputStream().write(out); 


     System.out.println(sj.toString()); 

     InputStream response = connection.getInputStream(); 

     @SuppressWarnings("resource") 
     Scanner scan = new Scanner(response); 
     String responsebody = scan.useDelimiter("\\A").next(); 
     System.out.println(responsebody); 



    } catch (IOException e) { 

     e.printStackTrace(); 
    } 

} 

如果有人可以對代碼有什麼問題進行說明，那麼將不勝感激。

Answer 1

在打開InputStream之前，必須刷新OutputStream。以下是我爲執行POST請求而創建的方法。

private String doPost(String urlString, LinkedHashMap<String, String> params) throws Exception { 
    //...make the content 
    StringBuilder content = new StringBuilder(); 
    //...append params 
    boolean first = true; 
    for (Map.Entry<String, String> entry : params.entrySet()) { 
     if (!first) { 
      content.append("&"); 
     } else { 
      first = false; 
     } 
     content.append(entry.getKey()).append("=").append(URLEncoder.encode(entry.getValue(), charset)); 
    } 
    //... send POST request 
    URL url = new URL(urlString); 
    HttpURLConnection con; 
    con = (HttpURLConnection) url.openConnection(); 
    con.setDoInput(true); 
    con.setDoOutput(true); 
    con.setUseCaches(false); 
    try (OutputStreamWriter writer = new OutputStreamWriter(con.getOutputStream(), charset)) { 
     writer.write(content.toString()); 
     writer.flush(); 
    } 
    //...get response 
    try (Scanner s = new Scanner(con.getInputStream(), charset)) { 
     String resp = s.useDelimiter("\\A").hasNext() ? s.next() : ""; 
     return resp; 
    } 
}