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我試圖將表單中的數據放入數據庫中。但我得到一個解析錯誤,說它找不到函數newuserid()。該功能是獲取數據庫中最新用戶標識的功能,並且爲新用戶提供+1功能。PHP調用未定義的函數newuserid()
爲什麼這不起作用?我似乎無法在互聯網上找到任何有關此事的信息。
下面的代碼片段:
/**
* newuserid - Creates a userid for every user, to link up to other services
*/
function newuserid() {
//Get latest userid
$q = "SELECT userid FROM blog_users ORDER BY userid DESC LIMIT 1";
$latest_userid = mysqli_query($this->connection, $q);
$userid = $latest_userid + 1;
return $userid;
}
/**
* addNewUser - Inserts the given (username, password, email)
*/
function addNewUser($userdata){
//Account
$username = $userdata['username'];
$password = $userdata['password'];
//Personal Information
$first_name = $userdata['first_name'];
$last_name = $userdata['last_name'];
$bdate = $userdata['bdate'];
//Address
$address = $userdata['address'];
$street_number = $userdata['street_number'];
$city = $userdata['city'];
$postal_code = $userdata['postalcode'];
//Phone & Email
$email = $userdata['email'];
$phone = $userdata['phone'];
$userid = newuserid();
$q = "INSERT INTO ".TBL_USERS." VALUES ('$username', '$password', '$userid', '$first_name', '$last_name', '$bdate', '$address', '$street_number', '$city', '$postal_code', '$email', '$phone')";
return mysqli_query($this->connection, $q);
}
是否有人知道如何解決這個問題,或者重新編寫了一塊?對不起,我不知道很多關於PHP的知識,所以我可能會用錯誤的方法來解決某些問題。
請幫我看看這個問題。
請出示使用完整和準確的錯誤你得到的消息! – Rizier123 2015-01-15 18:38:13
完整的錯誤消息:致命錯誤:調用未定義的函數newuserid()在/var/www/vhosts/ostrealyceum.net/giel-jan.ostrealyceum.net/include/login/database.php上線143 – sloeberGJ 2015-01-15 21:51:22
我的答案應該修復你的問題,如果是這樣,你可以接受最有幫助的答案,並解決你的問題(只需在答案左側選中標記)! – Rizier123 2015-01-15 21:54:29