XSLT 1.0集團通過標籤

Question

我有以下XML數據：

<result> 
<row> 
<CountryId>26</CountryId> 
<CountryName>United Kingdom</CountryName> 
<NoOfNights>1</NoOfNights> 
<AccommodationID>6004</AccommodationID> 
<RoomID>1</RoomID> 
<RoomName>Double for Sole Use</RoomName> 
<RatePlanID>1</RatePlanID> 
<RoomRatePlan>Advance</RoomRatePlan> 
<NoOfSameTypeRoom>0</NoOfSameTypeRoom> 
<RoomSize/> 
<Max_Person>1</Max_Person> 
<RackRate>189</RackRate> 
<CurrencySymbol>&pound;</CurrencySymbol> 
<NoOfRoomsAvailable>4</NoOfRoomsAvailable> 
<Rate>79.00</Rate> 
<RatePerDay>27 Mar 2013_79.00</RatePerDay> 
</row> 
<row> 
<CountryId>26</CountryId> 
<CountryName>United Kingdom</CountryName> 
<NoOfNights>1</NoOfNights> 
<AccommodationID>6004</AccommodationID> 
<RoomID>1</RoomID> 
<RoomName>Double for Sole Use</RoomName> 
<RatePlanID>2</RatePlanID> 
<RoomRatePlan>Standard</RoomRatePlan> 
<NoOfSameTypeRoom>0</NoOfSameTypeRoom> 
<RoomSize/> 
<Max_Person>1</Max_Person> 
<RackRate>189</RackRate> 
<CurrencySymbol>&pound;</CurrencySymbol> 
<NoOfRoomsAvailable>5</NoOfRoomsAvailable> 
<Rate>89.00</Rate> 
<RatePerDay>27 Mar 2013_89.00</RatePerDay> 
</row> 
<row> 
<CountryId>26</CountryId> 
<CountryName>United Kingdom</CountryName> 
<NoOfNights>1</NoOfNights> 
<AccommodationID>6004</AccommodationID> 
<RoomID>2</RoomID> 
<RoomName>Double Room</RoomName> 
<RatePlanID>1</RatePlanID> 
<RoomRatePlan>Advance</RoomRatePlan> 
<NoOfSameTypeRoom>0</NoOfSameTypeRoom> 
<RoomSize/> 
<Max_Person>2</Max_Person> 
<RackRate>199</RackRate> 
<CurrencySymbol>&pound;</CurrencySymbol> 
<NoOfRoomsAvailable>5</NoOfRoomsAvailable> 
<Rate>89.00</Rate> 
<RatePerDay>27 Mar 2013_89.00</RatePerDay> 
</row> 
</result> 

我對上面的XML XSLT是這樣的：

<?xml version="1.0" encoding="utf-8" ?> 

<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
       version="1.0"> 

    <xsl:output omit-xml-declaration="yes" indent="yes" method="xml" /> 
    <xsl:strip-space elements="*"/> 

    <!-- Default template : ignore unrecognized elements and text --> 
    <xsl:template match="*|text()" /> 

    <!-- Match document root : add hotels element and process each children node of result --> 
    <xsl:template match="/"> 
    <hotels> 
     <!-- We assume that the XML documents are always going to follow the structure: 
      result as the root node and xml_acc elements as its children --> 
     <xsl:for-each select="result/row"> 
     <result> 
      <hotel_rooms> 
      <xsl:element name="hotel_id"> 
       <xsl:value-of select="AccommodationID"/> 
      </xsl:element> 
      <xsl:apply-templates /> 
      </hotel_rooms> 
      <xsl:element name="Rate"> 
      <xsl:element name="RoomRatePlan"> 
       <xsl:value-of select="RoomRatePlan"/> 
      </xsl:element> 
      <xsl:element name="numeric_price"> 
       <xsl:value-of select="Rate"/> 
      </xsl:element> 
      </xsl:element> 
     </result> 
     </xsl:for-each> 
    </hotels> 
    </xsl:template> 

    <!-- Elements to be copied as they are --> 

    <xsl:template match="NoOfNights|RoomName|RoomSize|Max_Person|RackRate|RatePerDay|CurrencySymbol|NoOfRoomsAvailable|RoomDescription|RoomFacilities|PolicyComments|Breakfast|Policy|Message"> 
    <xsl:copy-of select="." /> 
    </xsl:template> 

    <xsl:template match="Photo_Max60"> 
    <RoomImages> 
     <Photo_Max60> 
     <xsl:value-of select="." /> 
     </Photo_Max60> 
     <Photo_Max300> 
     <xsl:value-of select="../Photo_Max300" /> 
     </Photo_Max300> 
     <Photo_Max500> 
     <xsl:value-of select="../Photo_Max500" /> 
     </Photo_Max500> 
    </RoomImages> 
    </xsl:template> 
</xsl:stylesheet> 

在XSLT 1.0，我想按房間ID和酒店ID。所以在上面的數據中，我想要這樣的結果。

<hotels> 
    <result> 
     <hotel_rooms> 
     <hotel_id>6004</hotel_id> 
     <NoOfNights>1</NoOfNights> 
     <RoomID>1</RoomID> 
     <RoomName>Double for Sole Use</RoomName> 
     <RoomSize/> 
     <Max_Person>1</Max_Person> 
     <RackRate>189</RackRate> 
     <CurrencySymbol>&pound;</CurrencySymbol> 
     <NoOfRoomsAvailable>4</NoOfRoomsAvailable> 
     <RatePerDay>27 Mar 2013_79.00</RatePerDay> 
    </hotel_rooms> 
    <Rate> 
    <RoomRatePlan>Advance</RoomRatePlan> 
    <numeric_price>79.00</numeric_price> 
    <RoomRatePlan>Standard</RoomRatePlan> 
     <numeric_price>89.00</numeric_price> 
    </Rate> 
    </result> 
    </result> 
    <hotels> 

我要爲上面的XML輸出I need.please幫助XSLT文件..

Answer 1

Muenchian方法：

<?xml version="1.0" encoding="utf-8" ?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> 
    <xsl:output indent="yes" /> 
    <xsl:key name="room-per-hotel" match="result" use="concat(hotel_rooms/hotel_id, '-', hotel_rooms/RoomID)" /> 
    <xsl:template match="/"> 
     <hotels> 
      <xsl:for-each select="hotels/result[count(. | key('room-per-hotel', concat(hotel_rooms/hotel_id, '-', hotel_rooms/RoomID))[1]) = 1]"> 
       <xsl:sort select="concat(hotel_rooms/hotel_id, '-', hotel_rooms/RoomID)" /> 
       <result> 
        <xsl:copy-of select="hotel_rooms"/> 
        <Rate> 
         <xsl:copy-of select="key('room-per-hotel', concat(hotel_rooms/hotel_id, '-', hotel_rooms/RoomID))/Rate/*"/> 
        </Rate> 
       </result> 
      </xsl:for-each> 
     </hotels> 
    </xsl:template> 
</xsl:stylesheet> 

Working example

Answer 2

既不好你的投入也不是你想要的結果是良好的形成與標籤沒有被正確關閉並存在實體引用£一個未聲明的實體，但如果你想用XSLT 1.0組則有使用Muenchian grouping看看下面的XSLT 1.0示例：

<xsl:stylesheet 
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    version="1.0"> 

<xsl:output indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:key name="group" match="result" use="concat(hotel_rooms/hotel_id, '|', hotel_rooms/RoomID)"/> 

<xsl:template match="hotels"> 
    <xsl:copy> 
    <xsl:apply-templates select="result[generate-id() = generate-id(key('group', concat(hotel_rooms/hotel_id, '|', hotel_rooms/RoomID))[1])]"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="result"> 
    <xsl:copy> 
    <xsl:copy-of select="hotel_rooms"/> 
    <Rate> 
     <xsl:copy-of select="key('group', concat(hotel_rooms/hotel_id, '|', hotel_rooms/RoomID))/Rate/*"/> 
    </Rate> 
    </xsl:copy> 
</xsl:template> 

</xsl:stylesheet> 

它把

<hotels> 
<result> 
    <hotel_rooms> 
    <hotel_id>6004</hotel_id> 
    <NoOfNights>1</NoOfNights> 
    <RoomID>1</RoomID> 
    <RoomName>Double for Sole Use</RoomName> 
    <RoomSize/> 
    <Max_Person>1</Max_Person> 
    <RackRate>189</RackRate> 
    <CurrencySymbol>pound</CurrencySymbol> 
    <NoOfRoomsAvailable>4</NoOfRoomsAvailable> 
    <RatePerDay>27 Mar 2013_79.00</RatePerDay> 
</hotel_rooms> 
<Rate> 
<RoomRatePlan>Advance</RoomRatePlan> 
<numeric_price>79.00</numeric_price> 
</Rate> 
</result> 
<result> 
<hotel_rooms> 
    <hotel_id>6004</hotel_id> 
    <NoOfNights>1</NoOfNights> 
    <RoomID>1</RoomID> 
    <RoomName>Double for Sole Use</RoomName> 
    <RoomSize/> 
    <Max_Person>1</Max_Person> 
    <RackRate>189</RackRate> 
    <CurrencySymbol>pound</CurrencySymbol> 
    <NoOfRoomsAvailable>5</NoOfRoomsAvailable> 
    <RatePerDay>27 Mar 2013_89.00</RatePerDay> 
</hotel_rooms> 
    <Rate> 
    <RoomRatePlan>Standard</RoomRatePlan> 
    <numeric_price>89.00</numeric_price> 
    </Rate> 
</result> 
</hotels> 

到

<hotels> 
    <result> 
    <hotel_rooms> 
     <hotel_id>6004</hotel_id> 
     <NoOfNights>1</NoOfNights> 
     <RoomID>1</RoomID> 
     <RoomName>Double for Sole Use</RoomName> 
     <RoomSize /> 
     <Max_Person>1</Max_Person> 
     <RackRate>189</RackRate> 
     <CurrencySymbol>pound</CurrencySymbol> 
     <NoOfRoomsAvailable>4</NoOfRoomsAvailable> 
     <RatePerDay>27 Mar 2013_79.00</RatePerDay> 
    </hotel_rooms> 
    <Rate> 
     <RoomRatePlan>Advance</RoomRatePlan> 
     <numeric_price>79.00</numeric_price> 
     <RoomRatePlan>Standard</RoomRatePlan> 
     <numeric_price>89.00</numeric_price> 
    </Rate> 
    </result> 
</hotels>