???達到500的最大遞歸限制

-2

我試圖運行時收到以下消息（adpcm_encoder）。???達到500的最大遞歸限制

??? Maximum recursion limit of 500 reached. Use set(0,'RecursionLimit',N) 
to change the limit. Be aware that exceeding your available stack space can 
crash MATLAB and/or your computer. 

Error in ==> fileparts

我在許多網站搜索了這個問題，但沒有找到具體的解決方案。

代碼：

function adpcm_y = adpcm_encoder(raw_y) 



Y = wavread('two.wav'); 
Y_en = adpcm_encoder(Y); 


IndexTable = [-1, -1, -1, -1, 2, 4, 6, 8, -1, -1, -1, -1, 2, 4, 6, 8]; 

StepSizeTable = [7, 8, 9, 10, 11, 12, 13, 14, 16, 17, 19, 21, 23, 25, 28, 31, 34, 37, 41, 45, 50, 55, 60, 66, 73, 80, 88, 97, 107, 118, 130, 143, 157, 173, 190, 209, 230, 253, 279, 307, 337, 371, 408, 449, 494, 544, 598, 658, 724, 796, 876, 963, 1060, 1166, 1282, 1411, 1552, 1707, 1878, 2066, 2272, 2499, 2749, 3024, 3327, 3660, 4026, 4428, 4871, 5358, 5894, 6484, 7132, 7845, 8630, 9493, 10442, 11487, 12635, 13899, 15289, 16818, 18500, 20350, 22385, 24623, 27086, 29794, 32767]; 

prevsample = 0; 
previndex = 1; 

Ns = length(raw_y); 
n = 1; 

raw_y = 32767 * raw_y;   % 16-bit operation 

while (n <= Ns) 
predsample = prevsample; 
index = previndex; 
step = StepSizeTable(index); 

diff = raw_y(n) - predsample; 
if (diff >= 0) 
    code = 0; 
else 
    code = 8; 
    diff = -diff; 
end 

tempstep = step; 
if (diff >= tempstep) 
    code = bitor(code, 4); 
    diff = diff - tempstep; 
end 
tempstep = bitshift(tempstep, -1); 
if (diff >= tempstep) 
    code = bitor(code, 2); 
    diff = diff - tempstep; 
end 
tempstep = bitshift(tempstep, -1); 
if (diff >= tempstep) 
    code = bitor(code, 1); 
end 

diffq = bitshift(step, -3); 
if (bitand(code, 4)) 
    diffq = diffq + step; 
end 
if (bitand(code, 2)) 
    diffq = diffq + bitshift(step, -1); 
end 
if (bitand(code, 1)) 
    diffq = diffq + bitshift(step, -2); 
end 

if (bitand(code, 8)) 
    predsample = predsample - diffq; 
else 
    predsample = predsample + diffq; 
end 

if (predsample > 32767) 
    predsample = 32767; 
elseif (predsample < -32768) 
    predsample = -32768; 
end 

index = index + IndexTable(code+1); 

if (index < 1) 
    index = 1; 
end 
if (index > 89) 
    index = 89; 
end 

prevsample = predsample; 
previndex = index; 

adpcm_y(n) = bitand(code, 15); 
%adpcm_y(n) = code; 
n = n + 1; 
end

來源

2011-12-17 Eng muslima

這是發生，因爲你有沒有停車條件遞歸調用自身的函數。它是無限循環的遞歸等價物。

問題是函數的第二行：

function adpcm_y = adpcm_encoder(raw_y) 

    Y = wavread('two.wav'); 
    Y_en = adpcm_encoder(Y);

功能的第二行再次遞歸調用函數，但因爲沒有停止條件，繼續，直到你遇到的最大遞歸限制錯誤。

來源

2011-12-17 22:39:43

如何才能達到最大遞歸極限誤差？我該怎麼辦？ – 2011-12-17 23:00:48

@ user1103780一般來說，有兩種方法可以讓人想起：你可以有一個正確的函數遞歸地處理一個大問題，或者你可能有一個總是碰到遞歸限制的錯誤函數。你的函數屬於後一類，因爲除了前兩行之外，它沒有運行任何東西。無論您將遞歸限制設置爲什麼，都不重要，因爲'adpcm_y'的確可以無限遞歸。我不確定你想通過'adpcm_y'中的遞歸調用來完成什麼，但是它現在所做的不可能是你想要的。 – 2011-12-17 23:06:50

-1

在Matlab的工作空間試試這個：

set(0, 'RecursionLimit', 100000)

然後再次運行你的代碼。

來源

2013-04-04 15:35:40

???達到500的最大遞歸限制

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