Python Tkinter條目（）計算

Question

我目前正在嘗試使用python在tkinter的幫助下構建一個GUI計算器。當我按下按鈕時（例如：按鈕5和5出現在條目（））中，我設置了所有按鈕，並與我的輸入（）欄互動。

剩下要做的唯一事情實際上是執行出現在entry（）中的數學公式。例如，如果我在輸入欄中輸入5 + 5 * 2，我將如何在更新後將答案顯示在條目（）中？所以基本上我所要求的是有人幫助我做到這一點！

我已經提供了下面的代碼和計算器的屏幕截圖。另外，請不要將此舉報爲重複或將此問題標記爲帖子，（我正在研究此問題，因爲我對最後一個問題沒有幫助，所以請幫助年輕的python程序員！）。另外我要求你不要給我提供鏈接，因爲我已經閱讀了tkinter上的每一個可能的鏈接，並且仍然不知道我在做什麼。

這裏是我的代碼：

import sys 
from tkinter import * 
from PIL import Image, ImageTk 

#ACTIONS: 
def clear(): 
    #Action: Clears the entry(). 
    txtDisplay.delete(0,END); 
    return; 

def update_Entry(inputValue): 
    #Updates the entry when a button is pressed. 
    currentText = num1.get(); 
    update = num1.set(currentText + inputValue); 

#Parent Window. 
root = Tk(); 
root.title('Calculator ++ [1.7.2]'); 
root.geometry('350x450'); 

#Main entry. 
num1 = StringVar(); 
txtDisplay = Entry(root, textvariable = num1, relief=RIDGE, bd = 10, width=33, insertwidth = 1, font = 40, justify=RIGHT); 
txtDisplay.place(x=15, y=10); 
txtDisplay.focus(); 

print(txtDisplay.get()) 

#Buttons: 
zeroButton = Button(root, text='0', width=20, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('0')); 
zeroButton.place(x=17,y=382); 
oneButton = Button(root, text='1', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('1')); 
oneButton.place(x=17, y=302); 
twoButton = Button(root, text='2', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('2')); 
twoButton.place(x=100, y=302); 
threeButton = Button(root, text='3', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('3')); 
threeButton.place(x=182, y=302); 
fourButton = Button(root, text='4', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('4')); 
fourButton.place(x=17, y=222); 
fiveButton = Button(root, text='5', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('5')); 
fiveButton.place(x=100, y=222); 
sixButton = Button(root, text='6', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('6')); 
sixButton.place(x=182, y=222); 
sevenButton = Button(root, text='7', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('7')); 
sevenButton.place(x=17, y=142); 
eightButton = Button(root, text='8', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('8')); 
eightButton.place(x=100, y=142); 
ninthButton = Button(root, text='9', width=8, height=3, bg='LightBlue', fg='red', command=lambda:update_Entry('9')); 
ninthButton.place(x=182, y=142); 

decimalButton = Button(root, text='.', width=8, height=3, bg='powder blue', command=lambda:update_Entry('.')); 
decimalButton.place(x=182, y=382); 
equalButton = Button(root, text='=', width=8, height=8, bg='Lightgreen', command=lambda:update_Entry('=')); 
equalButton.place(x=264, y=307); 
plusButton = Button(root, text='+', width=8, height=3, bg='gray', command=lambda:update_Entry('+')); 
plusButton.place(x=264, y=222); 
minusButton = Button(root, text='-', width=8, height=3, bg='gray', command=lambda:update_Entry('-')); 
minusButton.place(x=264, y=142); 
multiplyButton = Button(root, text='x', width=8, height=3, bg='gray', command=lambda:update_Entry('*')); 
multiplyButton.place(x=264, y=66); 
divideButton = Button(root, text='÷', width=8, height=3, bg='gray', command=lambda:update_Entry('/')); 
divideButton.place(x=182, y=66); 
clearButton = Button(root, text='Clear (CE)', width=20, height=3, command = clear, bg='Orange'); 
clearButton.place(x=17, y=66); 

#Locks the parent windows size. 
root.maxsize(350,450); 
root.minsize(350,450); 

#Parent window's background color: 
root.configure(background = 'black'); 
root.mainloop(); 

截圖：

Answer 1

對於一些這個簡單，嘗試有此作爲command爲您equalButton：

def evaluate(): 
    currentText = num1.get() 
    try: 
     num1.set(str(eval(currentText))) 
    except SyntaxError: 
     num1.set('<ERROR>')