bash腳本if和while條件

Question

我有執行以下bash腳本麻煩

：

#!/bin/bash 
response=" " 
while ["$response" != "q"]; do 
echo -n "Please enter a response"; read response 
done 

ALSO

!/bin/bash 
response="x" 

if ["$response" = "x"] 
then 
echo "the value is x" 
fi 

還有什麼可能的錯誤是什麼？

Answer 1

你的while和if語句間隔錯誤。

while [ "$response" != "q" ]; do etc 

您需要括號和雙引號之間的空格。