2013-04-02 35 views
22

如何解壓一個數組中的Ruby這樣的例子在Python:如何解壓縮數組?

>>> x = [1, 2, 3] 
>>> y = [4, 5, 6] 
>>> zipped = zip(x, y) 
>>> zipped 
[(1, 4), (2, 5), (3, 6)] 
>>> x2, y2 = zip(*zipped) 
>>> x == list(x2) and y == list(y2) 

回答

36

使用transpose

> zipped = x.zip(y) 
=> [[1, 4], [2, 5], [3, 6]] 
> x2, y2 = zipped.transpose 
> x2 
=> [1, 2, 3] 
> y2 
=> [4, 5, 6] 
+2

如果'x.size> y.size','transpose'是不太逆因爲它會在'y2'的末尾添加'nil'。如果兩個原始文件都不包含使用'zipped.transpose.map(&:compact)'的零'恢復原件。 – dbenhur

+0

@dbenhur這是真的。 –