燒瓶 - 獲取值

Question

我想從用戶輸入到搜索框中的「名稱」和「大小」值中獲取值。

但顯而易見的問題是，我試圖得到值從method: "POST" hmtl形式。 而我的html操作只是引用{{ url_for('main') }} html，而不是要在{{url_for（'search'）}} html中檢索這些值的位置。

這裏是模板：

import sqlite3 
from flask import Flask,render_template, url_for, redirect, request 


app = Flask(__name__) 
conn = sqlite3.connect('shoes.db', check_same_thread=False) 
c = conn.cursor() 

@app.route("/", methods=["GET", "POST"]) 
def main(): 

    if request.method == 'GET': 
     return render_template('main.html') 

    elif request.method == 'POST': 
     name = request.form.get('name') 
     size = request.form.get('size') 
     return redirect(url_for('search')) 


@app.route("/search/", methods=["GET", "POST"]) 
def search(): 

    # Need to get the 'name' and 'search' values from input, so this way is incorrect. 
    name = request.args.get("name") 
    size = request.args.get("size")  

    c.execute("SELECT * FROM shoes WHERE name LIKE ? AND sizes LIKE ? ORDER BY price", 
        ('%'+name+'%','%'+size+'%')) 

    p = c.fetchall() 

    url = [p[i][0] for i in range(len(p))] 
    names = [p[i][1] for i in range(len(p))] 
    prices = [p[i][2] for i in range(len(p))] 
    sizes = [p[i][3] for i in range(len(p))] 
    shoe_type = [p[i][4] for i in range(len(p))] 

    return render_template('search.html' , url=url, names=names, prices=prices, 
          sizes=sizes, shoe_type=shoe_type) 


if __name__ == '__main__': 
    app.run(debug=True) 

main.html中：

{% extends "layout.html" %} 
{% block content %} 

<form action = "{{ url_for('main') }}" class="form" method = "POST" > 

     <h1>Soccer Shoes Finder</h1> 
     <div class="line-separator"></div> 

      <div class="container-fluid"> 
       <input name = "name" type="text" placeholder="Name"/> 
       <input name = "size" type="text" placeholder="Size"/> 
       <button class="glyphicon glyphicon-search" aria-hidden="true"></button> 
      </div> 

</form> 

{% endblock %} 

search.html：

{% extends "layout.html" %} 
{% block content %} 


    <div class= "container"> 
    <h2>Results:</h2> 
    <table class="table table-striped"> 
    <thead> 
    <tr> 
     <th>url</th> 
     <th>Name</th> 
     <th>Prices</th> 
     <th>Sizes</th> 
     <th>Shoe Type</th> 
    </tr> 
    </thead> 
    <tbody> 
    {% for i in range(url|length) %} 
    <tr> 
     <td><a href={{url[i]}}>aa</td> 
     <td>{{names[i]}}</td> 
     <td>${{prices[i]}}</td> 
     <td>{{sizes[i]}}</td> 
     <td>{{shoe_type[i]}}</td> 
    </tr> 
    {% endfor %} 
    </tbody> 
    </table> 
    </div> 
{% endblock %} 

任何人都知道我怎麼能做到這一點？希望我說的是有道理的。謝謝。

Answer 1

簡化您的主要途徑，似乎沒有理由在這裏發佈的數據：通過您的main.html中神社內改變這一行

@app.route("/") 
def main(): 
    return render_template('main.html') 

POST的數據，而不是直接向您的搜索端點模板：

<form action="{{ url_for('search') }}" class="form" method="POST"> 

由於這個頁面呈現依賴於具有表單數據我只是將它設置爲只接受POST方法，但是這 你決定。您需要使用request.form（或request.values，如果您還想支持查詢字符串GET方法）訪問這裏的值。

@app.route("/search/", methods=["POST"]) 
def search(): 
    name = request.form.get("name") 
    size = request.form.get("size") 

假設你的數據庫的代碼工作的這剩下的應該按預期工作