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您好我想通過使用webrequest類將XML數據發送到Web服務器。我通過發佈單個變量成功完成。但是我不能將下面的解析XML包含進去。請幫助我。使用WebRequest發送XML類
static void Main(string[] args)
{
using (XmlReader reader = XmlReader.Create("filepath"))
{
while (reader.Read())
{
switch (reader.NodeType)
{
case XmlNodeType.Element:
Console.WriteLine("Start Elemet {0}", reader.Name);
break;
case XmlNodeType.Text:
Console.WriteLine("Text Node: {0}", reader.Value);
break;
case XmlNodeType.EndElement:
Console.WriteLine("EndElement {0}", reader.Name);
break;
default:
Console.WriteLine("Other node {0} with value {1}",
reader.NodeType, reader.Value);
break;
}
}
}
}
下面是我從MSDN網站得到的代碼,並通過這個我想給上面的XML數據。
public class WebRequestPostExample
{
public static void Main()
{
// Create a request using a URL that can receive a post.
WebRequest request = WebRequest.Create ("http://www.contoso.com/PostAccepter.aspx ");
// Set the Method property of the request to POST.
request.Method = "POST";
// Create POST data and convert it to a byte array.
string postData = "This is a test that posts this string to a Web server.";
byte[] byteArray = Encoding.UTF8.GetBytes (postData);
// Set the ContentType property of the WebRequest.
request.ContentType = "application/x-www-form-urlencoded";
// Set the ContentLength property of the WebRequest.
request.ContentLength = byteArray.Length;
// Get the request stream.
Stream dataStream = request.GetRequestStream();
// Write the data to the request stream.
dataStream.Write (byteArray, 0, byteArray.Length);
// Close the Stream object.
dataStream.Close();
// Get the response.
WebResponse response = request.GetResponse();
// Display the status.
Console.WriteLine (((HttpWebResponse)response).StatusDescription);
// Get the stream containing content returned by the server.
dataStream = response.GetResponseStream();
// Open the stream using a StreamReader for easy access.
StreamReader reader = new StreamReader (dataStream);
// Read the content.
string responseFromServer = reader.ReadToEnd();
// Display the content.
Console.WriteLine (responseFromServer);
// Clean up the streams.
reader.Close();
dataStream.Close();
response.Close();
}
}
我想接收端是在PHP中。
定義 「不能」。你期望發生什麼,發生了什麼? – CodeCaster 2014-12-02 10:32:50
我只想發送使用上述webrequest類的XML數據。 – 2014-12-02 10:38:44
我的意思是爲什麼不工作。 – CodeCaster 2014-12-02 10:42:20