2014-12-03 68 views
0

嗨,我寫了一些代碼的數學程序,並希望一些幫助來驗證用戶輸入。我希望程序能夠在用戶忽略一個問題並簡單地按下下一個問題的回車鍵時再次向他們展示完全相同的問題,並通知他們必須嘗試每個問題。繼承人的代碼,我到目前爲止如何驗證Python的檢查沒有用戶輸入

import time 
import random 
msg=0 
questionsAsked=0 
score=0 
op = ["-","*","+"] 
username= input("What is your name? ") 
print("Okay "+username+ " lets begin the test. Good luck!") 
praise= ["Well done!","Great job!", "Spot on!", "Perfect!"] 
wrong = ["Unlucky!", "Not quite", "Incorrect"] 
def actual(num1,num2,operation): 
    actual=eval(str(num1) + operation + (str(num2))) 
    return actual 

def useranswer(num1,num2,operation): 
    useranswer=int(input(str(num1)+operation+str(num2)+"= ")) 
    return useranswer 

while questionsAsked <10: 
    num1 = random.randint(0,12) 
    num2 = random.randint(0,12) 
    operation = random.choice(op) 
    praiseMsg= random.choice(praise) 
    wrongMsg= random.choice(wrong) 

    if useranswer(num1,num2,operation) != actual(num1,num2,operation): 
     print(wrongMsg)      
    else: 
     print(praiseMsg) 
     score= score+1 
    questionsAsked=questionsAsked+1 


else: 
    if score>5: 
     msg= str("Well done "+username+"! You scored over 50%") 
    else: 
     msg=str("Better luck next time " + username) 
    print("You scored " +str(score)+ " out of 10. \n" +msg) 
    time.sleep(3) 

回答

1
username = raw_input("What is your name? ") 
while not username: 
    username = raw_input("Not understood. What is your name?") 

你可以在一個函數把這個包:

def insist_upon_answer(prompt): 
    answer = raw_input(prompt) 
    while not answer: 
     answer = raw_input("All questions must be answered. {}".format(prompt) 
    return answer 

,並稱之爲:

name = insist_upon_answer("What is your name?") 
0

像triphook的回答,爲Python 3 :

username = input("Input: ") 
while username=="": 
    username = input("Input (again): ")