有沒有辦法說匹配一個或多個定義的子序列/分組的實例？

Question

require 'rubygems' 
require 'differ' 

original = "Epic lolcat fail bellmead drive!" 
current = "Epic wolfman fail bellmead dr!" 

diff = Differ.diff_by_word(current, original).to_s 

puts diff # => "Epic {"lolcat" >> "wolfman"} fail bellmead {"drive" >> "dr"}! 

diff =~ /(\{"[a-zA-Z0-9]*" >> "[a-zA-Z0-9s]*"\})/ 

puts "#{$1} to #{$2} #{$3} to #{$4}" 
# => lolcat to wolfman to 

# Desired output: lolcat to wolfman to drive to dr 

Answer 1

我不知道「不同」，但如何：

require 'rubygems' 
require 'differ' 

original = "Epic lolcat fail bellmead drive!" 
current = "Epic wolfman fail bellmead dr!" 

diff = Differ.diff_by_word(current, original).to_s 

puts diff # => "Epic {"lolcat" >> "wolfman"} fail bellmead {"drive" >> "dr"}! 

captures = diff.scan /\{"([a-zA-Z0-9]*)" >> "([a-zA-Z0-9s]*)"\}/ 

captures.each {|c| puts "#{c[0]} to #{c[1]}" }