我有一個腳本驗證表單(使用jQuery Validate),然後提交數據。它目前運行良好,但現在我需要添加一個複選框,並且我不清楚如何使用jQuery/ajax提交值。我是否需要包含諸如$('#checkBox').attr('checked');
之類的內容?如果是這樣,我如何將它傳遞給ajax?jquery驗證 - 點擊「提交」檢查複選框
此外,當我點擊「提交」,沒有完成表格,複選框自動檢查自己。這是爲什麼發生?
的jquery:
<script>
$(document).ready(function(){
$("#formid").validate({
rules: {
name: "required",
email: {
required: true,
email: true
},
mobile: {
required: true,
minlength: 10
},
news: {
required: false,
}
},
messages: {
name: "Please enter your name",
email: "Please enter a valid email address",
mobile: "Please enter your mobile number"
},
submitHandler: function() {
var name = $('#name').attr('value');
var email = $('#email').attr('value');
var mobile = $('#mobile').attr('value');
var news = $('#news').attr('value');
$.ajax({
type: "POST",
url: "ajax.php",
data: $("#formid").serialize(),
success: function(){
$('form#formid').hide();
$('div.success').fadeIn();
}
});
return false;
}
});
});
</script>
形式:
<form id="formid" method="post">
<fieldset>
<div>
<label for="name">Name</label>
<input type="text" id="name" name="name" class="required" />
</div>
<div>
<label for="email">Email</label>
<input type="text" id="email" name="email" class="required" />
</div>
<div>
<label for="mobile">Mobile</label>
<input type="text" id="mobile" name="mobile" class="required" />
</div>
<label for="news"><p>Please don’t send me ongoing news</p>
<input type="checkbox" id="news" name="news" value="No" />
<label for="submit1" id="submit"><span> </span>
<input id="submit1" type="submit" name="submit" value="Submit"/>
</label>
</fieldset>
</form>
它的確如此。輝煌:-)非常感謝!多麼愚蠢的錯誤...... – circey 2012-08-01 02:31:06
@circey我們都做到了;) – 2012-08-01 02:32:07