我想一次顯示一個形狀, 我很難如何刪除所選的無線電。html5基於無線電的帆布顯示形狀
function display() {
var canvas = document.getElementById('displaycake_sketch');
context = canvas.getContext('2d');
//context.clearRect(0, 0, canvas.width, canvas.height);
context.beginPath();
if (document.getElementById('color1').checked) {
context.strokeStyle = "#FF0000";
} else if (document.getElementById('color2').checked) {
context.strokeStyle = "#0000FF";
}
if (document.getElementById('shape1').checked) {
context.arc(95, 50, 40, 0, 2 * Math.PI);
context.stroke();
}
if (document.getElementById('shape2').checked) {
context.rect(50, 27, 50, 100);
context.stroke();
}
}
$(function() {
var drawObject = $('#displaycake_sketch').sketch();
var oldRedraw = drawObject.data('sketch').redraw;
drawObject.data('sketch').redraw = function() {
oldRedraw.call(this);
display();
}
$(".tools a").eq(0).attr("style", "color:#fba557");
$(".tools a").click(function() {
$(".tools a").removeAttr("style");
$(this).attr("style", "color:#000");
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="http://intridea.github.io/sketch.js/lib/sketch.js"></script>
<canvas id="displaycake_sketch"></canvas>
<div> <input type="radio" id="shape1" name="shape_design" value="CIRCLE" onchange="display()"/> O
<input type="radio" id="shape2" name="shape_design" value="RECTANGLE" onchange="display()"/> [] </div>
<div> <input type="radio" id="color1" name="color_design" value="RED" onchange="display()"/> RED
<input type="radio" id="color2" name="color_design" value="BLUE" onchange="display()"/> BLUE </div>
<div class="tools">
<a href="#displaycake_sketch" class="btn btn-primary" data-tool="marker"> Marker</a>
<a href="#displaycake_sketch" class="btn btn-primary" data-tool="eraser"> Eraser</a>
</div>
我很好的免費抽獎(素描啄),只是形狀的顯示...
希望有人能幫助我...我讓我感到困惑的是我從不同渠道獲得的所有這些代碼。預先感謝您..
了'//context.clearRect(0之前添加
context.clearRect(0, 0, canvas.width, canvas.height);
清除畫布,0,canvas.width,帆布.height);'在評論中,它解決了你的問題(我認爲...)。這種說法所做的是清除你的畫布(以使它變空)。 – KarelG@KarelG我沒有評論它,因爲素描/塗鴉部分(標記)它不會出現。 – Khyana