CakePHP的3.X分選得到的計數值

經過一番研究，我創造了這個發現的聲明，但預期它不工作：CakePHP的3.X分選得到的計數值

public $virtualFields = array(
    'count' => "SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id" 
); 

public function trainingsPerLocationChartData(){ 
$this->loadModel('Locations'); 
$locationsDiagramData = $this->Locations->find('all', array(
      'fields' => array(
       'locations.id', 
       'locations.description', 
       'locations.count' /* virtuel field */ 
      ) 
     ));

的聲明將是這樣的：

'sql' => 'SELECT locations.id AS `locations__id`, locations.description AS `locations__description`, locations.count AS `locations__count` FROM locations Locations'

虛擬域根本不被識別。我做錯了什麼？

更新：我發現我不得不這樣稱呼它：

'count' => "(SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id) AS `counter`"

我加了（）周圍的選擇。

$locationsDiagramData = $this->Locations->find('all') 
      ->select(['locations.id', 'locations.description', $this->virtualFields['count']]);

但我仍然得到一個錯誤的SQL語法：

SELECT locations.id AS `locations__id`, locations.description AS `locations__description`, (SELECT COUNT(plans_trainings.id) FROM plans_trainings, trainings, projects WHERE plans_trainings.training_id = trainings.id AND projects.location_id = locations.id AND plans_trainings.project_id = projects.id) AS `counter` AS (SELECT COUNT(plans_trainings__id) FROM plans_trainings, trainings, projects WHERE plans_trainings FROM locations Locations

「最後」的問題似乎只有這部分AS counter後：

AS（SELECT COUNT（plans_trainings__id）FROM計劃培訓，培訓，項目哪裏計劃培訓

這是聲明中斷的地方！任何想法如何解決？如果我在phpmyadmin中運行語句並刪除這個提到的部分，該語句正常工作，並帶來正確的結果！

更新2：這是明擺着的語句：

select 
       locations.id, 
    locations.description, 
    (
           select 
               count(plans_trainings.id) 
           from 
               plans_trainings, 
      trainings, 
      projects 
           where 
               plans_trainings.training_id = trainings.id 
               and projects.location_id = locations.id 
               and plans_trainings.project_id = projects.id 
    ) as 'Anzahl' 
from 
       locations;

來源

2016-12-30 user1555112

有CakePHP中3沒有虛擬領域了...用正確的[**子查詢**]（http://book.cakephp.org/3.0/en/orm/query-builder.html#subqueries）並將其傳遞給[**'select（）'**]（http：// book。 cakephp.org/3.0/en/orm/query-builder.html#selecting-data）。 – ndm

嘗試這種在控制器

$this->loadModel('Locations'); 
$this->loadModel('PlansTrainings'); 
$this->loadModel('Trainings'); 
$this->loadModel('Projects'); 
$sub_query=$this->PlansTrainings->find()->select(['cnt1'=>'count(PlansTrainings.id)'])->join([ 
     [ 
      'table' => 'trainings', 
      'alias' => 'Trainings', 
      'type' => 'INNER', 
      'conditions' => 'PlansTrainings.training_id=Trainings.id', 
     ], 
     [ 
      'table' => 'projects', 
      'alias' => 'Projects', 
      'type' => 'INNER', //LEFT, RIGHT... 
      'conditions' => ['Projects.location_id=PlansTrainings.id','PlansTrainings.project_id=Projects.id'], 
     ], 
]); 
$locationsDiagramData = $this->Locations->find()->select(['id', 'description','count'=>$sub_query]);

來源

2016-12-30 14:58:21

CakePHP的3.X分選得到的計數值

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