嘗試以下操作:
$product = $_POST['product'];
$sql_query3 = "Select tbl_mixed_case.related_product
FROM tbl_mixed_case JOIN tbl_product_info
ON tbl_product_info.id = tbl_mixed_case.prod_code_id
AND tbl_product_info.product + ' ' = '$product' LIMIT 2" ;
$result3 = mysqli_query($dbconfig, $sql_query3);
var $dispProd
while ($products = mysqli_fetch_array($result3, MYSQL_ASSOC)) {
$dispProd[] = $products;
}
header('Content-Type: application/json');//add the proper header
echo json_encode(['products'=>$dispProd]);//convert to json
在你的Ajax成功功能
你做到以下幾點:
success:function(data) {
$('#product1').val(data.products[0]);//add the first value to a input with the id of product1
$('#product2').val(data.products[1]);
}
我已經包含了AJAX請求和形式輸入如下:
function submitdata() {
var product = document.getElementById("product").value;
// Returns successful data submission of associated products
var dataString = 'product=' + product;
// AJAX code to submit form.
$.ajax({
type: "POST",
url: "product.php",
data: 'application/json; charset=utf-8',
cache: false,
success: function(data) {
alert(data);
$('#product1').val(data.products[0]);//add the first value to a input with the id of product1
$('#product2').val(data.products[1]);
}
});
}
<input type="text" value="" placeholder="" class="" id="product1" name="product1" tabindex="-1"/>
<input type="text" value="" placeholder="" class="" id="product2" name="product2" tabindex="-1"/>
'tbl_product_info.product +'''的作用是什麼? – madalinivascu
您需要選擇您在表格中的唯一標識符(如唯一的ID)。所以,像'SELECT id,field'。然後,將你的'mysqli_fetch_array()'改爲'mysqli_fetch_assoc()'和'print_r($ products)'來查看你的數據 – andrew