的 「id」 屬性,但不是 「名」 我有4個文件,如下圖所示:爲什麼我只能拉從MySQL
PostVent.php:
<!DOCTYPE html>
<html lang = "en">
<head>
<meta charset = "utf-8" />
<link rel="stylesheet" type="text/css" href="PostLinkStyle.css" />
<style type="text/css">
legend.standout{font-weight: bold; font-size: 24pt;}
</style>
<title>Post Vent</title>
</head>
<body>
<!-- start header div -->
<div id="header">
<h3>SomeVent</h3>
</div>
<div id="wrap">
<form action="" method="post">
<div class="row">
<div class="large-8 small-centered columns">
<fieldset>
<legend id="legend">Post Vent</legend>
<div class="row">
<div class="small-12 columns">
<label for="email">Email</label>
<input type="text" id="email" size="35"></input>
</div>
</div>
<div class="row">
<div class="small-8 columns">
<?php
//Include database configuration file
include('dbConfig.php');
include('index.php');
//Get all state data
$query = $db->query("SELECT **name** FROM states");
//Count total number of rows
$rowCount = $query->num_rows;
?>
<select name="state" id="state">
<option value="">Select State</option>
<?php
if($rowCount > 0){
while($row = $query->fetch_array()){
echo '<option value="'.$row['name'].'">'.$row['id'].'</option>';
}
}else{
echo '<option value="">States not available</option>';
}
?>
</select>
<select name="county" id="county">
<option value="">Select County</option>
</select>
</div>
</div>
的index.php:
<script src="jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#state').on('change',function(){
var stateID = $(this).val();
if(stateID){
$.ajax({
type:'POST',
url:'ajaxData.php',
data:'id='+stateID,
success:function(html){
$('#county').html(html);
}
});
}else{
$('#county').html('<option value="">Select state first</option>');
}
});
$('#county').on('change',function(){
var countyID = $(this).val();
if(countyID){
$.ajax({
type:'POST',
url:'ajaxData.php',
data:'id='+stateID,
success:function(html){
$('#county').html(html);
}
});
}else{
$('#city').html('<option value="">Select state first</option>');
}
});
});
</script>
ajax.php:
<?php
//Include database configuration file
include('dbConfig.php');
if(isset($_POST["id"]) && !empty($_POST["id"])){
//Get all county data
$query = $db->query("SELECT name FROM counties...");
//Count total number of rows
$rowCount = $query->num_rows;
//Display county list
if($rowCount > 0){
echo '<option value="">Select County</option>';
while($row = $query->fetch_assoc()){
echo '<option value="'.$row['id'].'">'.$row['name'].'</option>';
}
}else{
echo '<option value="">County not available</option>';
}
}
?>
再加上我DAT基礎配置文件(我不認爲它需要顯示)。我試圖根據選定的狀態動態填充縣下拉菜單。
我對此非常感興趣,並將我在網上提供的許多教程放在一起。我的問題是這個。我的縣菜單怎麼沒有填充?我試圖將選定的狀態ID屬性發布到ajax以獲得具有相同ID的縣。看不到有什麼問題。
尋找'SELECT ID,名字從states' ??? – devpro
您正在使用'SELECT name FROM states'名稱查詢並打印結果中的'echo'';'??? – devpro