Spring Security with vaadin maven project中的數據庫

Question

我有一個vaadin maven項目，我在spring security中集成，所以我能夠看到spring security的默認登錄形式。 現在我想從postgres數據庫獲得用戶請幫助我嗎？你有任何tuto或書嗎？感謝「SA很多

Answer 1

作爲例子（尊重羅蘭Krügers例子）春季啓動應用+ SpringSecurity + Vaadin4Spring＃Hibernate，就必須在application.properties定義以下屬性：

# DATASOURCE 
spring.datasource.url=jdbc:postgresql://localhost/myDB 
spring.datasource.username=myuser 
spring.datasource.password=mypwd 
spring.datasource.driverClassName=org.postgresql.Driver 
spring.datasource.xa.data-source-class-name=org.postgresql.xa.PGXADataSource 
spring.datasource.pinGlobalTxToPhysicalConnection="true" 

# one transaction manager via view 
spring.jpa.open-in-view=true 
# for mapping models and attributes to table names and column names 
spring.jpa.hibernate.naming_strategy=org.hibernate.cfg.EJB3NamingStrategy 
spring.jta.default-transaction-timeout=2000 

使用application.properties在您的應用程序下面的註釋添加到您的主類：

@PropertySources({ 
    @PropertySource({"classpath:application.properties"}) 
}) 

現在，用戶的實體可以是這樣的：

import javax.persistence.Column; 
import javax.persistence.Entity; 
import javax.persistence.Id; 
import javax.persistence.GeneratedValue; 
import javax.persistence.GenerationType; 

@Entity 
@Table(name = "USER") 
public class User { 

    @Id 
    @GeneratedValue(strategy = GenerationType.IDENTITY) 
    @Column(name = "ID", nullable = false, updatable = false) 
    private Long id; 

    @Column(name = "LAST_NAME", nullable = false) 
    private String lastName; 

    @Column(name = "FIRST_NAME", nullable = false) 
    private String firstName; 

    @Column(name = "LOGGED_IN") 
    private boolean loggedIn; 

    public Long getId() { 
     return id; 
    } 

    public void setId(Long id) { 
     this.id = id; 
    } 

    public String getLastName() { 
     return lastName; 
    } 

    public void setLastName(String lastName) { 
     this.lastName = lastName; 
    } 

    public String getFirstName() { 
     return firstName; 
    } 

    public void setFirstName(String firstName) { 
     this.firstName = firstName; 
    } 

    public boolean isLoggedIn() { 
     return loggedIn; 
    } 

    public void setLoggedIn(boolean loggedIn) { 
     this.loggedIn = loggedIn; 
    } 
} 

之後，你必須定義對Hibernate的存儲庫接口：

/** 
*Spring auto repository for database access of User objects. 
**/ 
public interface UserRepository extends JpaRepository<User, Long> { 

    Optional<User> findOneByName(String userName); 
} 

現在你可以做這樣的事情在你的登錄方法：

... 
vaadinSecurity.login(userName.getValue(), passwordField.getValue()); 
Optional<User> ouser = userRepository.findOneByName(userName); 
if (ouser.isPresent()) { 
    User user = ouser.get(); 
    user.setLoggedIn(true); 
} 
...