我的數據使用dput
在下面呈現。將數據幀列表轉換爲單個數據幀並更改列名稱
dat <- structure(list(`60` = structure(c(25.2142857142857, 25.2142857142857,
25.2142857142857, 16.8333333333333, 6.18181818181818, 6.45454545454545,
39.3076923076923, 17.8, 30.2307692307692, 31.9090909090909, 338.872342659885,
338.872342659885, 338.872342659885, 312.566239187662, 108.98770426029,
132.000329498368, 295.499325777881, 289.05210119046, 279.319320138619,
282.696361655751), .Dim = c(10L, 2L), .Dimnames = list(NULL,
c("CanCov", "Aspect"))), `100` = structure(c(22.2285714285714,
21.8285714285714, 22.2285714285714, 17.4285714285714, 7.54054054054054,
5.51351351351351, 32.8823529411765, 18.0285714285714, 31.3125,
32.5833333333333, 328.300126247896, 336.611388179775, 328.300126247896,
288.830157290819, 132.674633942446, 122.597267778504, 295.162359106757,
254.508961455896, 280.326744650874, 287.386617538886), .Dim = c(10L,
2L), .Dimnames = list(NULL, c("CanCov", "Aspect"))), `500` = structure(c(10.786941580756,
10.7688787185355, 10.8489702517162, 10.7628278221209, 14.1569301260023,
12.9438717067583, 12.8735632183908, 10.8551724137931, 20.729667812142,
23.3722794959908, 195.270942450807, 195.540990751048, 195.662725661548,
190.688980052674, 165.038240066186, 133.772446928244, 198.45485951978,
188.942107644257, 203.862336021767, 217.567077176237), .Dim = c(10L,
2L), .Dimnames = list(NULL, c("CanCov", "Aspect"))), `1000` = structure(c(10.3804067602406,
10.3746059042706, 10.381156930126, 9.8993981083405, 13.26243567753,
13.6912732474964, 11.3125, 9.73461208130547, 17.5430539609644,
18.8537492844877, 174.841410186063, 174.803449739022, 174.777413321887,
169.181037352303, 148.07213983955, 145.460198642085, 157.562633627451,
162.484978829108, 159.688505118645, 163.433969343022), .Dim = c(10L,
2L), .Dimnames = list(NULL, c("CanCov", "Aspect")))), .Names = c("60",
"100", "500", "1000"))
我有一個包含四個元素(名爲60,100,500和1000)的列表。
> str(dat)
List of 4
$ 60 : num [1:10, 1:2] 25.21 25.21 25.21 16.83 6.18 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:2] "CanCov" "Aspect"
$ 100 : num [1:10, 1:2] 22.23 21.83 22.23 17.43 7.54 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:2] "CanCov" "Aspect"
$ 500 : num [1:10, 1:2] 10.8 10.8 10.8 10.8 14.2 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:2] "CanCov" "Aspect"
$ 1000: num [1:10, 1:2] 10.4 10.4 10.4 9.9 13.3 ...
..- attr(*, "dimnames")=List of 2
.. ..$ : NULL
.. ..$ : chr [1:2] "CanCov" "Aspect"
我想製作一個單一的8乘10數據框,列對應於列表名稱。具體而言,這些列將標記爲CanCov_60,Aspect_60,CanCov_100,...,CanCov_1000,Aspect_1000,其中CanCov_60和Aspect_60的值將來自具有相應名稱的列表。
我懷疑ldply
是最好的功能使用,但似乎無法連接點。
解釋你改變了什麼。 – lyndact
你說得對,這樣做可以完成工作,但是對於循環,尤其是成長中的物體來說,這不是一個好習慣。不必要的將數據幀轉換爲矩陣並返回。 – Heroka
1-赫羅卡,你的解決方案有點優雅,謝謝..今天我學到了一些東西。 2-列表包含矩陣,我只在最後將矩陣轉換爲數據幀。 3-有趣的事實。要求是產生一個數據框,所有的代碼都返回矩陣類對象!我的代碼是唯一一個返回data.frame,但我得到了一個負1 ...大聲笑。 –