從php類中的函數返回一個變量（返回不工作只回聲作品）

Question

我有一個PHP類，突出顯示文本中提到的名稱鏈接。它可以搜索給定文本中的@character並檢查名稱跟隨那個角色。

問題是，當我負責處理文本的方法（public function process_text ($text_txt){}）時，類的返回值沒有打印出來。但是，當我將return語言結構更改爲print或echo時，解析是成功的，並且打印出處理的字符串。我需要return而不是print，以便能夠將返回字符串存儲在我的CMS的評論表中。

請參閱完整的代碼如下，並建議：

class mentions { 
    public $print_content = ''; 
    private $m_names = array(); 
    private $m_denied_chars = array(
     "@", 
     "#", 
     "?", 
     "¿" 
    ); 
    private $m_link = "http://example.com/"; // + name of the username, link or whatever 

    /* 
    * this class can also be used for specific links 
    * start editing from here 
    * */ 

    public function add_name ($name) { 
     array_push($this->m_names, $name); 
    } 

    public function process_text ($text_txt) { 
     $expl_text = explode(" ", $text_txt); 

     /* 
     * a character will be ignores which can be specified next this comment 
     * :) 
     * */ 

     $sp_sign = "@"; // this is what you can change freely... 

     for ($i = 0; $i < count($expl_text); ++$i) { 
      $spec_w = $expl_text[$i]; 
      $print_link = false; 
      $name_link = ""; 
      if ($spec_w[0] == $sp_sign) { // then can be a mention... 
       $name = ""; 
       $break_b = false; 
       for ($x = 1; $x < strlen($spec_w); ++$x) { 
        if ($spec_w[$x] == '.' || $spec_w[$x] == ",") { 
         if (in_array($name, $this->m_names)) { 
          $print_link = true; 
          $name_link = $name; 
          break; 
         } 
        } 
        if (in_array($spec_w[$x], $this->m_denied_chars)) { 
         $break_b = true; 
         break; 
        } 
        $name .= $spec_w[$x]; 
       } 
       if ($break_b == true) { 
        $print_link = false; 
        break; 
       } else { 
        if (in_array($name, $this->m_names)) { 
         $print_link = true; 
         $name_link = $name; 
        } 
       } 
      } 
      if ($print_link == true) { 
       $this->print_content = "<a href=\"".$this->m_link."".$name_link."\">".$spec_w."</a>"; 
       if ($i < count($expl_text)) $this->print_content .= " "; 

      } else { 
       $this->print_content = $spec_w; 
       if ($i < count($expl_text)) $this->print_content .= " "; 
      } 
      return $this->print_content; 
     } 
    } 
} 
###### create new class object and process raw data ###### 
$mentions = new mentions; 
$raw_data = 'Hello, @Angelina. I am @Bob_Marley.'; 

$expr = '#(?:^|\W)@([\w-]+)#i'; 
preg_match_all($expr, $raw_data, $results); 
if(!empty($results[1])) { 

    foreach($results[1] as $user) { 
     $mentions->add_name($user); 
    } 
    /* 
    ------------------------------------ 
    */ 
    $commenData = $mentions->process_text($raw_data); 
    echo $commenData; 
} 

Answer 1

答案由@Terminus。如果你在循環中有一個返回值，循環（和整個函數）將被中斷，返回的值將立即返回。這就是它的工作原理。試圖寫出這是一個很好的答案，但不能。最終有點改寫你的課程。 ideone.com/vaV0d2請注意，我遺留在var_dump測試中，並且由ideone提供的輸出不允許鏈接標記顯示爲html，但如果您從服務器運行它，它將是正確的