PHP在窗口中找不到文件

Question

我在Windows 10計算機上構建了一個基於WAMP服務器的PHP服務器。我想要做的是當我發送一個GET請求時，show_files.php應該返回一個JSON對象給我。 JSON對象包含我電腦上路徑F:\NetEaseMusic\download中的文件名。然後，我使用文件名向download_file.php發送POST請求，並返回一個數據流，以便我可以下載文件。當我使用HttpURLConnection時，一切正常。但是，當我嘗試發送POST請求使用套接字時，download_file.php可以獲得file_name參數，但它在F:\NetEaseMusic\download中找不到目標文件。我展示了代碼。 這是

這是download_file.php

<?php 
if(empty($_POST["file_name"])) 
{ 
    echo "NO_FILE_NAME\n"; 
    print_r($_POST); 
    exit(); 
} 
$path = iconv("utf-8", "GB2312","F:\\NetEaseMusic\\download\\".$_POST["file_name"]); 
//$path = "F:\\NetEaseMusic\\download\\".$_POST["file_name"]; 
if (!file_exists ($path)) { 
    echo "FILE_NOT_FOUND\n"; 
    echo "F:\\NetEaseMusic\\download\\".$_POST["file_name"]."\n"; 
    print($path); 
    exit(); 
} 
$file_size = filesize($path); 
//header("Content-type: application/octet-stream"); 
//header("Accept-Ranges: bytes"); 
//header("Accept-Length:".$file_size); 
//header("Content-Disposition: attachment; filename=".$path); 
$file = fopen($path, "r"); 
while(!feof($file)) 
{ 
    echo fread($file, 1024); 
} 
exit(); 
?> 

這是我的客戶端代碼來下載文件。首先，我建立一個HTTP POST請求，

private void downloadFileBySocket(String urlString, String fileName) 
{ 

    try{ 
     StringBuilder sb = new StringBuilder(); 
     String data = URLEncoder.encode("file_name", "utf-8") + "=" + URLEncoder.encode(fileName, "utf-8") + "\r\n"; 
     //String data = "&file_name="+fileName; 
     sb.append("POST " + urlString + " HTTP/1.1\r\n"); 
     sb.append("Host: 10.206.68.242\r\n"); 
     sb.append("Content-Type: application/x-www-form-urlencoded\r\n"); 
     sb.append("Content-Length: " + data.length() + "\r\n"); 
     sb.append("\r\n"); 
     sb.append(data + "\r\n"); 

     //sb.append(URLEncoder.encode("file_name", "utf-8") + "=" + URLEncoder.encode(fileName, "utf-8") + "\r\n"); 

     System.out.println(sb.toString()); 

     URL url = new URL(urlString); 
     Socket socket = new Socket(url.getHost(), url.getPort()); 
     BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(socket.getOutputStream(), "utf-8")); 
     writer.write(sb.toString()); 
     writer.flush(); 


     File file = new File("./" + fileName); 
     DataOutputStream out = null; 
     DataInputStream in = null; 
     try{ 
      out = new DataOutputStream(new FileOutputStream(file)); 
      in = new DataInputStream(socket.getInputStream()); 
      byte[] buffer = new byte[1024]; 
      int readBytes = 0; 
      while((readBytes = in.read(buffer)) != -1) 
      { 
       out.write(buffer, 0, readBytes); 
      } 
      out.flush(); 
     }catch (Exception e1) 
     { 
      e1.printStackTrace(); 
     }finally { 
      try{ 
       if(in != null) 
       { 
        in.close(); 
       } 
       if(out != null) 
       { 
        out.close(); 
       } 
      }catch (Exception e2) 
      { 
       e2.printStackTrace(); 
      } 
     } 
     socket.close(); 

    }catch (Exception e) 
    { 
     e.printStackTrace(); 
    } 

} 

和我的主[]方法

public static void main(String[] args) 
{ 
    SocketTest socketTest = new SocketTest(); 
    socketTest.downloadFileBySocket(SocketTest.downloadFileUrl, "小胡仙兒 - 【二胡】霜雪千年.mp3"); 
} 

Answer 1

簡單的方法：

using System.Net; 
WebClient webClient = new WebClient(); 
webClient.DownloadFile("example.com/myfile.txt", @"c:/myfile.txt");