在集合中不存在流口水

Question

如果集合沒有特定的對象，我需要激發規則。

AuditAssignment可作爲問題的事實。

AuditAssignment有一個屬性「requiredSkill」

審計任務有一個屬性「審計師」

審計對象有「資格」的名單，這是「requiredSkill」的集合

現在，我需要檢查，如果auditassignment對象中的核數師的資格有requiredSkill

下面是我試過，但不起作用樣品規則。

rule "checkIfAuditSkillIsMatching" 
    when 
     $auditAssignment : AuditAssignment($neededSkill : requiredSkill.getSkillCode()) 

     $auditor : Auditor($auditorSkills : qualifications) 
     not exists (Skill (skillCode == $neededSkill) from $auditorSkills ) 

    then 
     System.out.println(" **** " + $neededSkill); 
     scoreHolder.addHardConstraintMatch(kcontext, -1); 
end 

我曾嘗試下面的一個以及

rule "checkIfAuditSkillIsMatching" 
    when 

     $validAuditorCount : Number (intValue < 1 ) from accumulate (
      $auditor : Auditor($auditorSkills: qualifications) 
      and exists AuditAssignment(auditor == $auditor , 
        $auditorSkills.contains(requiredSkill)) , 
      count($auditor) 

     ) 

    then 
     scoreHolder.addHardConstraintMatch(kcontext, -1); 
end 

Answer 1

下面的配置工作

rule "checkIfAuditSkillIsMatching" 
    when 
     $auditAssignment : AuditAssignment($neededSkill : requiredSkill , 
        $assignedAuditor : auditor) 

     $auditor : Auditor(this == $assignedAuditor , !qualifications.contains($neededSkill)) 

    then 
     scoreHolder.addHardConstraintMatch(kcontext, -1); 
end 

Answer 2

這是建議使用收集的屬性方法來獲得你所需要的邏輯值。

rule "checkIfAuditSkillIsMatching" 
when 
    $auditAssignment: AuditAssignment($neededSkill: requiredSkill.getSkillCode()) 
    $auditor: Auditor($auditorSkills: qualifications, 
         ! $auditorSkills.contains($neededSkill)) 
then 
    //...no suitably qualified auditor 
end