在android中查詢xml解析

我正在開發一個android應用程序，我必須從.Net webservice獲取數據最初webservice的方法返回簡單的字符串。這很好，我的代碼工作正常，順利地獲取字符串。但是我的問題在方法返回對象時開始，我知道對象以XML形式保存數據。我也通過調試我的代碼來確認它，結果對象保存下面給出的數據。在android中查詢xml解析

<?xml version="1.0" encoding="utf-8"?> 

<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> 

<soap:Body> 

<UserInfoResponse xmlns="http://tempuri.org/"> 

<UserInfoResult> 

<UserName>Himanshu</UserName> 

<Email>[email protected]</Email> 

</UserInfoResult> 

</UserInfoResponse> 

</soap:Body> 

</soap:Envelope>

和我的代碼使用的Web服務是： -

public void objData(){ 

     SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME2); 
     Log.d("request", request.toString()); 

     SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
     Log.d("envelope", envelope.toString()); 

     envelope.dotNet = true; 
     envelope.setOutputSoapObject(request); 
     Log.d("envelope", envelope.toString()); 

     HttpTransportSE aht = new HttpTransportSE(URL); 
     aht.debug=true; 
     Log.d("aht", aht.toString()); 

     try 
     { 
      aht.call(OBJ_SOAP_ACTION, envelope); 
      SoapPrimitive results = (SoapPrimitive)envelope.getResponse(); 
      System.out.println("results="+results); 
      tv4.setText(""+results); 
     } 
     catch (Exception e) 
     { 
      tv4.setText(e.getClass().toString()); 
      Log.d("Error",e.getClass().toString()); 
     } 

    }

對象results包含XML data.Now我的問題是，當我使用的代碼打印對象的數據tv4.setText(""+results);它給我class java.lang.ClassCastException。我知道這是不正確的方法來獲取對象的XML數據，我不得不解析它。但我不知道如何解析對象。所以請幫助我解析XML包含object.Any幫助將高度讚賞。提前告知。

來源

2012-02-13 himanshu

不能使用SoapPrimitive複雜的對象，你要投的響應如下

SoapObject response = (SoapObject) envelope.getResponse();

然後，如果你想將它轉換爲實體對象（類似於你通過.net web服務發送的對象），你必須這樣做。

實體類

public class EmLogin { 

private String _id; 

private String _pwd; 


public EmLogin() { 
} 

public String getId() { 
    return _id; 
} 

public void setId(String id) { 
    this._id = id; 
} 

public String getPwd() { 
    return _pwd; 
} 

public void setPwd(String pwd) { 
    this._pwd = pwd; 
} 

//this is the place you are setting the SoapObject as a param 
public EmLogin(SoapObject so) throws ParseException { 

    this._id = so.getProperty("Id").toString();// these are the properties of your xml objs 
    this._pwd = so.getProperty("PasswordHash").toString(); 

}}

如下retrived soapobject設置爲實體類的方式。

EmLogin = null; 
if (yourSoapObject!= null) { 
    // here you are parsing the soapobject to the emlogin object as a param 
    emLogin = new EmLogin(yourSoapObject); 
}

來源

2012-02-13 06:51:19 Rakhita

如果您需要更多說明，請與我聯繫... – Rakhita 2012-02-13 06:52:02