2014-11-21 68 views
-1

我有以下列表:如何使用scala在元組列表中查找字符串?

List(
    (List("vmname"),"myNetwork3",10,"vSwitch0",List(),"192.168.20.2","cisco WS-C3560E-48PD","GigabitEthernet0/43","sky"), 
    (List("vmname"),"myNetwork",0,"vSwitch0",List("name1", "name2", "name3", "name4"),"192.168.20.2","cisco WS-C3560E-48PD","GigabitEthernet0/43","sky") 
) 

而且我想找到列表列表元素串"name1"

我想下面的輸出:

(List("vmname"),"myNetwork",0,"vSwitch0",List("name1", "name2", "name3", "name4"),"192.168.20.2","cisco WS-C3560E-48PD","GigabitEthernet0/43","sky") 

如何使用斯卡拉得到上面的輸出?

+0

的第5個元素列表中的「名1」中的所有條目這是一個任務?有兩個人問非常類似的問題 – 2014-11-21 13:32:13

+0

@paul不..我也找到類似的問題..我能夠在列表中找到字符串,但無法在列表中找到它 – Yogesh 2014-11-21 13:34:27

回答

2
l.filter(._5 contains "name1") 

返回與屬於每個條目

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