我不知道如何關閉一個簡單的彈出框

Question

對不起，簡單的問題。 我不確定是否所有這些都很重要，但我會提及它以防萬一。 ：當用戶點擊一個鏈接，這是發生了什麼：

function begin(some info) is called->Makes an Ajax request to backend PHP-> 
PHP calls the callback function->Callback function calls another JS function that creates a popup-> 
In the popup creating function, The Save button is assigned a function that makes an ajax request and sends PHP some user input.-> 
PHP makes a callback to another function that does nothing. 

在這裏，這是一個拼彈出框的功能。

function collection(name, description, data){ 
    var json = data; 
    var cont = openSitePopup("400","300"); 
    //We create div objects. 
    var namecell = ce("div","sitePopupCell"); 
    //Stuff 
    // We create a button and assign the createProducts Method to it. 
    var sbtbutton = createBtn("submitObject","SAVE","createProducts()"); 
    //We append all the div objects to the popup. 
    cont.appendChild(namecell); 
    //.. 
} 

function openSitePopup(width,height) { 

//try to center the popup if values are not passed 
var xPos = (getWinWidth()/2) - (width/2) + sl; 
var yPos = (getWinHeight()/2) - (height/2) + st; 

sitepopupwin = ge("sitePopupWin"); 
clearElement(sitepopupwin); 

var winhandle = ce("div","","sitePopupHandle"); 

sitepopupwin.style.display = "block"; 
//Other style assignments. 

//closebutton 
var close = ce("img","sitePopupCloseBtn"); 
close.setAttribute("src",theme_path + "/images/icons/close.png"); 

//start adding goodies 
var mydiv = ce("div","sitePopupContainer"); 

winhandle.appendChild(close); 
winhandle.appendChild(createCleaner()); 
sitepopupwin.appendChild(winhandle); 
sitepopupwin.appendChild(mydiv); 

//return reference to the container for adding stuff 
return mydiv; 
} 

function createProducts() 
{ 
    //Some exciting Ajax stuff with a callback to writeNewFolder() 
} 

function writeNewFolder(data){ 
    //Nothing of interest here...yet. 
} 

現在，當我按在彈出的Save按鈕，請求被成功地進行，但彈出不會關閉。我知道Window.Close()函數，但它不起作用。 cont.Close()似乎是一個明顯的選擇，但在這種情況下，我得到這個錯誤：Uncaught TypeError: Object #<HTMLDivElement> has no method 'Close'因此，Cont只是一個div元素。 openSitePopup()方法只返回一個div。

感謝您的幫助。

編輯：

function ce(elementType,elementClass,elementId,txt) { 

var e = document.createElement(elementType); 

//add optional parameters 
if (elementId) e.setAttribute("id",elementId); 
if (elementClass) setClass(e,elementClass); 

//append extra text. If passed an object, append with without the textnode wrapper 
if (isData(txt)) { 
    if (typeof(txt)=="object") e.appendChild(txt); 
    else e.appendChild(ctnode(txt)); 
} 

return e; 

} 

希望的原創者不介意我張貼了他的一些代碼在這裏。那麼，它是免費的，開源的，所以它應該沒問題......我想。

編輯2：ge功能。這個很簡單。

function ge(element) { 
return document.getElementById(element); 
} 

Answer 1

你沒有張貼創建這不是一個window因此彈出的功能GE和CE不能.close()它

嘗試

ge('sitePopupWin').style.display='none';

或

var popup = ge('sitePopupWin'); 
popup.parentNode.removeChild(popup);