如何保存表中的$ _post

Question

即時提出如何創建一個表格，將$ _post thingy中的輸入保存到表格中，非常感謝！或者你能幫我修復這個代碼或創建一個新的工作請嗎？我需要你的幫助，請再次感謝！

<?php 

$servername = "localhost"; 
$username = "root"; 
$password = "root"; 
$dbname = "tsukishiro"; 

$id = $_POST['id']; 
$name = $_POST['name']; 
$comment = $_POST['comment']; 
$input = $_POST['input']; 


// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 

// Check connection 
if ($conn->connect_error) { 
die("Connection failed: " . $conn->connect_error); 
} 

$sql = "INSERT INTO connection(ID, name, comment, input) VALUES ('null', '$name', '$comment', 'input')"; 



if ($_SERVER["REQUEST_METHOD"] == "POST") { 
    if (empty($_POST["name"])) { 
    $nameErr = "Name is required"; 
    } else { 
    $name = test_input($_POST["name"]); 
    // check if name only contains letters and whitespace 
    if (!preg_match("/^[a-zA-Z ]*$/",$name)) { 
     $nameErr = "Only letters and white space allowed"; 
    } 
    } 

    if (empty($_POST["comment"])) { 
    $comment = ""; 
    } else { 
    $comment = test_input($_POST["comment"]); 
    } 


    if (empty($_POST["input"])) { 
    $input = ""; 
    } else { 
    $input = test_input($_POST["input"]); 
    } 



function test_input($data) { 
    $data = trim($data); 
    $data = stripslashes($data); 
    $data = htmlspecialchars($data); 
    return $data; 
} 

echo "<input type='text' name='id'>";<br><br> 
echo "<input type='text' name='name'>"; 
echo "<input type='text' name='comment'>"; 
echo "<input type='text' name='input'>"; 
echo "<input type='submit' name='submit'>"; 


if ($conn->query($sql) === TRUE) { 
echo "New record created successfully"; 
} else { 
echo "Error: " . $sql . "<br>" . $conn->error; 
} 



$conn->close(); 

?>` 

Answer 1

添加<form>標記。

<form name="form_name" action="your_page.php" method="post"> 
    <input type='text' name='id'> 
    <input type='text' name='name'> 
    <input type='text' name='comment'> 
    <input type='text' name='input'> 
    <input type='submit' name='submit'> 
</form> 

更新時間：

<?php 

$servername = "localhost"; 
$username = "root"; 
$password = "root"; 
$dbname = "tsukishiro"; 


// Create connection 
$conn = new mysqli($servername, $username, $password, $dbname); 

// Check connection 
if ($conn->connect_error) { 
die("Connection failed: " . $conn->connect_error); 
} 

function test_input($data) { 
    $data = trim($data); 
    $data = stripslashes($data); 
    $data = htmlspecialchars($data); 
    return $data; 
} 


if ($_SERVER["REQUEST_METHOD"] == "POST") { 

    $id = $_POST['id']; 
    $name = $_POST['name']; 
    $comment = $_POST['comment']; 
    $input = $_POST['input']; 

    if (empty($_POST["name"])) { 
    $nameErr = "Name is required"; 
    } else { 
    $name = test_input($_POST["name"]); 
    // check if name only contains letters and whitespace 
    if (!preg_match("/^[a-zA-Z ]*$/",$name)) { 
     $nameErr = "Only letters and white space allowed"; 
    } 
    } 

    if (empty($_POST["comment"])) { 
    $comment = ""; 
    } else { 
    $comment = test_input($_POST["comment"]); 
    } 


    if (empty($_POST["input"])) { 
    $input = ""; 
    } else { 
    $input = test_input($_POST["input"]); 
    } 

    $sql = "INSERT INTO connection(ID, name, comment, input) VALUES ('null', '$name', '$comment', 'input')"; 

    if ($conn->query($sql) === TRUE) { 
    echo "New record created successfully"; 
    } else { 
    echo "Error: " . $sql . "<br>" . $conn->error; 
    } 

} 

$conn->close(); 

?> 
<form name="form_name" action="" method="post"> 
    <input type='text' name='id'> 
    <input type='text' name='name'> 
    <input type='text' name='comment'> 
    <input type='text' name='input'> 
    <input type='submit' name='submit'> 
</form> 

Answer 2

你錯過$符號的輸入變量

$sql = "INSERT INTO connection(ID, name, comment, input) VALUES ('null', '$name', '$comment', '$input')";