如何統計XMLList中的重複項目並將它們分配到ArrayCollection中？

Question

我下面的XMLList，

<party/> <party/> <party/> <party>A</party> <party>B</party> <party>C</party> <party>A</party> <party>B</party> <party>C</party> <party>D</party> <party>E</party> <party>D</party> <party>A</party> <party/> <party>C</party>

我想消除空白點，並做出一個ArrayCollection像（有個別政黨的數量），

塔爾=新ArrayCollection的（[{方： 「A」，Count：3}， {Party：「B」，Count：2}， {Party：「C」，Count：3}， {Party：「D」，Count：2}， {聚會：「E」，Count：1}， ]）;

在此先感謝。

Answer 1

這是未經測試，可能不是最有效的，但應該工作：

var partyDict:Dictionary = new Dictionary(); 
var parties:ArrayCollection = new ArrayCollection(); 

var xml:XML = <root><party/><party/><party/><party>A</party><party>B</party><party>C</party><party>A</party><party>B</party><party>C</party><party>D</party><party>E</party><party>D</party><party>A</party><party/><party>C</party></root>; 

for each (var p:XML in xml.party) { 
    var val:String = p.toString(); 
    if ((val != null) && StringUtil.trim(val).length > 0) { 
     if (partyDict[val] != null) { 
      partyDict[val] = (partyDict[val] as int) + 1; // may simply be able to do partyDict[val]++; 
     } else { 
      partyDict[val] = 1; 
     } 
    } 
} 

for (var key:Object in partyDict) { 
    var o:Object = new Object(); 
    o.Party = key; 
    o.Count = partyDict[key]; 
    parties.addItem(o); 
} 

Answer 2

如果有可能的各方的列表，它只是：

var partiesObjs:ArrayCollection = new ArrayCollection(); 

var xml:XML = <root><party/><party/><party/><party>A</party><party>B</party><party>C</party><party>A</party><party>B</party><party>C</party><party>D</party><party>E</party><party>D</party><party>A</party><party/><party>C</party></root>; 
var parties:Array = ["A","B","C","D"] 

for each(var p:String in parties){ 
    var count:int = xml..party.(toString() == p).length() 
    partiesObjs.addItem({Party:p, Count:count}) 
}