將1個C++循環轉換爲2個

我需要一些編程幫助。我寫了下面的代碼，但是我的老師說在讀數據文件時我需要使用2 for循環。我不知道該怎麼做......有什麼建議嗎？將1個C++循環轉換爲2個

我的代碼：

ifstream infile; 
infile.open("dive.txt"); 
for(int i = 0; i <= 6; i++) 
    infile >> contestantNames[i][0] >> contestantNames[i][1] >> judgeScores[i][0] >> judgeScores[i][1] >> judgeScores[i][2] >> judgeScores[i][3] >> judgeScores[i][4] >> judgeScores[i][5] >> judgeScores[i][6] >> judgeScores[i][7]; 
infile.close();

來源

2010-12-06 keepitcoder

你的老師可能希望你使用兩個嵌套循環，而不是手動從0到7。 – thkala 2010-12-06 04:02:06

你可以請你提供100個參賽者的例子嗎？（with`contestantNames [100] [100]`） – ruslik 2010-12-06 04:02:42

而不是repetitiously寫

infile >> contestantNames[0][0] >> contestantNames[0][1] >> judgeScores[0][0] >> judgeScores[0][1] >> judgeScores[0][2] >> judgeScores[0][3] >> judgeScores[0][4] >> judgeScores[0][5] >> judgeScores[0][6] >> judgeScores[0][7]; 
infile >> contestantNames[1][0] >> contestantNames[1][1] >> judgeScores[1][0] >> judgeScores[1][1] >> judgeScores[1][2] >> judgeScores[1][3] >> judgeScores[1][4] >> judgeScores[1][5] >> judgeScores[1][6] >> judgeScores[1][7]; 
infile >> contestantNames[2][0] >> contestantNames[2][1] >> judgeScores[2][0] >> judgeScores[2][1] >> judgeScores[2][2] >> judgeScores[2][3] >> judgeScores[2][4] >> judgeScores[2][5] >> judgeScores[2][6] >> judgeScores[2][7]; 
infile >> contestantNames[3][0] >> contestantNames[3][1] >> judgeScores[3][0] >> judgeScores[3][1] >> judgeScores[3][2] >> judgeScores[3][3] >> judgeScores[3][4] >> judgeScores[3][5] >> judgeScores[3][6] >> judgeScores[3][7]; 
infile >> contestantNames[4][0] >> contestantNames[4][1] >> judgeScores[4][0] >> judgeScores[4][1] >> judgeScores[4][2] >> judgeScores[4][3] >> judgeScores[4][4] >> judgeScores[4][5] >> judgeScores[4][6] >> judgeScores[4][7]; 
infile >> contestantNames[5][0] >> contestantNames[5][1] >> judgeScores[5][0] >> judgeScores[5][1] >> judgeScores[5][2] >> judgeScores[5][3] >> judgeScores[5][4] >> judgeScores[5][5] >> judgeScores[5][6] >> judgeScores[5][7]; 
infile >> contestantNames[6][0] >> contestantNames[6][1] >> judgeScores[6][0] >> judgeScores[6][1] >> judgeScores[6][2] >> judgeScores[6][3] >> judgeScores[6][4] >> judgeScores[6][5] >> judgeScores[6][6] >> judgeScores[6][7];

你寫一個for循環。

還有哪裏有重複？

來源

2010-12-06 04:02:37 ephemient

你的兩個for循環將

for (int i = 0; i <= 6; i++) { 
    infile >> contestantNames[i][0] >> contestantNames[i][1]; 
    for (int j = 0; j <= 7; j++) { 
     infile >> judgeScores[i][j]; 
    } 
}

你的教練要你judgeScores的是不斷線簡化成一個for循環是更簡單，更易於閱讀。

來源

2010-12-06 04:02:44 tmiddlet

ifstream infile; 
infile.open("dive.txt"); 

for (int i = 0; i <= 6; i++) 
{ 
    infile >> contestantNames[i][0] >> contestantNames[i][1]; 

    // The next part is what your teacher was talking about. 
    // You wrote judgeScores[i][0] >> judgeScores[i][1] >> ... 
    // seven times, which is pretty redundant. Programmers are *extremely* lazy 
    // so we loop constantly, wherever possible: 

    for (int j = 0; j <= 7; j++) 
    { 
    infile >> judgeScores[i][j]; 
    } 
} 

infile.close();

來源

2010-12-06 04:03:20 Blender

我認爲你的老師對所有的參賽者是指一次循環，再次循環到輸入每個選手的信息

所以嘗試這樣的事情（姓名和分數。）：

ifstream infile; 
infile.open("dive.txt"); 
for(int i = 0; i <= 6; i++) { 
    infile >> contestantNames[i][0] >> contestantNames[i][1]; 
    for (int j = 0; i <= 7; j++) { 
     infile >> judgeScores[i][j]; 
    } 
} 
infile.close();

注：括號不是必需的，因爲每個語句由一行組成。但是，這是規則的例外情況 - 如果for循環中有多條語句，則需要括號。（你可能知道）

來源

2010-12-06 04:04:34 Darel

你的老師可能希望你考慮的情況下，當有超過兩個的內容。沿着

nc = 6; // the number of contenstans 
for (int c=0; c<nc; c++) { 
    // other for loop here... 
}

來源

2010-12-06 04:06:20 ric0liva

驚喜各位老師的線東西甚至三個環路：

ifstream infile; 
infile.open("dive.txt"); 
for(int i = 0; i <= 6; i++) 
{ 
    for (int j = 0; j < 2; ++j) 
    { 
     infile >> contestantNames[i][j]; 
    } 

    for (int j = 0; j < 8; ++j) 
    { 
     infile >> judgeScores[i][j]; 
    } 
} 
infile.close();

來源

2010-12-06 04:30:05 detunized

把while循環的文件（EOF）的情況下，最終檢查有超過6行。壞數據的測試案例也不會傷害。

來源

2010-12-06 05:37:21 neckbeard

將1個C++循環轉換爲2個

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