如何獲得不同價值的每個表聯接

我建立了事件預訂網站的數據庫。現在我有一個關係到一到多用（eventTickets，eventSponsors，eventGuests）表關係活動表。如何獲得不同價值的每個表聯接

CREATE TABLE EVENT (
      EVENT_ID INTEGER NOT NULL AUTO_INCREMENT, 
      ORGANIZER_ID INTEGER NOT NULL, 
      name VARCHAR(30) NOT NULL, 
      picture VARCHAR(50) NULL, 
      venue VARCHAR(50) NOT NULL, 
     city VARCHAR(30) NOT NULL DEFAULT Ethiopia, 
     sub_city VARCHAR(50) NULL, 
     location VARCHAR(50) NOT NULL, 
     category VARCHAR(50) NOT NULL, 
     start_date DATE NOT NULL, 
     end_date DATE NOT NULL, 
     longitude DOUBLE NULL, 
     latitude DOUBLE NULL, 
     status VARCHAR(15) NOT NULL DEFAULT DRAFT, 
     discription TEXT NOT NULL, 
     country VARCHAR(30) NOT NULL DEFAULT Ethiopia, 
     end_time TIME NOT NULL, 
     start_time TIME NULL, 
     created_on TIMESTAMP NOT NULL DEFAULT TIMESTAMP(), 
     PRIMARY KEY (EVENT_ID), 
     FOREIGN KEY (ORGANIZER_ID) REFERENCES organizer(ORGANIZER_ID) ON DELETE CASCADE ON UPDATE CASCADE 

    ) ENGINE=INNODB; 

    CREATE TABLE SPONSORS (
      SPONSOR_ID INTEGER NOT NULL AUTO_INCREMENT, 
      EVENT_ID INTEGER NOT NULL, 
      name VARCHAR(50) NOT NULL, 
      image VARCHAR(50) NULL, 
      PRIMARY KEY (SPONSOR_ID), 
    FOREIGN KEY (EVENT_ID) REFERENCES event(EVENT_ID) ON DELETE CASCADE ON UPDATE CASCADE 

    ) ENGINE=INNODB; 



     CREATE TABLE GUESTS (
      GUEST_ID INTEGER NOT NULL AUTO_INCREMENT, 
     first_name VARCHAR(30) NOT NULL, 
     last_name VARCHAR(30) NOT NULL, 
     aka_name VARCHAR(50) NULL, 
     title VARCHAR(15) NULL, 
     bio VARCHAR(100) NULL, 
     image VARCHAR(50) NULL, 
     EVNT_ID INTEGER NOT NULL, 
     PRIMARY KEY (GUEST_ID), 
     FOREIGN KEY (EVENT_ID) REFERENCES event(EVENT_ID) ON DELETE CASCADE ON UPDATE CASCADE 

    ) ENGINE=INNODB; 

     CREATE TABLE EVENT_TICKETS (
      TICKET_ID INTEGER NOT NULL AUTO_INCREMENT, 
      EVENT_ID INTEGER NOT NULL, 
      name VARCHAR(20) NOT NULL, 
      type VARCHAR(20) NOT NULL, 
      price FLOAT(4) NOT NULL, 
      quantity INTEGER NOT NULL, 
      discription VARCHAR(255) NOT NULL, 
      sale_start DATE NOT NULL, 
      sale_end DATE NOT NULL, 
     active BOOL NOT NULL DEFAULT 0, 
     available INTEGER NOT NULL, 
     created_on TIMESTAMP NOT NULL DEFAULT NOW(), 
     PRIMARY KEY (TIK_ID) 
     FOREIGN KEY (EVENT_ID) REFERENCES event(EVENT_ID) ON DELETE CASCADE ON UPDATE CASCADE 

    ) ENGINE=INNODB;

現在我有事件表

 EVENT_ID | NAME 
     1  | firstEvent 
     2  | secondEvent

發起人表

SPONSOR_ID | EVENT_ID | name 
     1  | 1  | firstEventSponsor 
     2  | 2  | secondEventSponsor

客桌

GUEST_ID | EVENT_ID | first_name | last_name 
    1  |  1 | firstEvent | guest 
    2  |  2 | secondEvent| guest

和票表

TICKET_ID | EVENT_ID | type 
    1  |  1 | free 
    2  |  2 | secondEvent 
    3  |  1 | paid

我想從其他每個表的與特定事件來獲取所有相關領域，如果記錄存在或NULL，如果是沒有的。當我做了加入我收到重複其他表的記錄，直到結果集錶行計數匹配

這裏獲得最大的回報是我連接的結果集

SELECT `event`.`EVENT_ID` AS 'eventId' ,`event`.`name` AS 'eventName' , `venue` `TICKET_ID` AS 'ticketId', `eventTicket`.`type` AS 'ticketType', 
     `eventGuest`.`GUEST_ID` AS 'guestId', CONCAT(`eventGuest`.`first_name`, " ", `eventGuest`.`last_name`) AS 'guestName', 
     `eventSponsor`.`SPONSOR_ID` AS 'sponsorId', `eventSponsor`.`name` AS 'sponsorName', 
    FROM `event` 

    LEFT OUTER JOIN `eventTicket` ON `event`.`EVENT_ID` = `eventTicket`.`EVENT_ID` 
    LEFT JOIN `eventGuest` ON `eventTicket`.`EVENT_ID` = `eventGuest`.`EVENT_ID` 
    LEFT JOIN `eventSponsor` ON `eventGuest`.`EVENT_ID` = `eventSponsor`.`EVENT_ID` 

    WHERE `event`.`EVENT_ID` = 1 
    GROUP BY `event`.`EVENT_ID`, `eventTicket`.`TICKET_ID`, `eventGuest`.`GUEST_ID`, `eventSponsor`.`SPONSOR_ID` ;

這個返回設置這樣的結果

eventId | eventName | ticketId | type | guestId | guestName  | sponsorId  | sponsorName 
    1 | firstEvent | 1  | free | 1  |firstEventGuest | 1 | firstEventSponsor 
    1 | firstEvent | 2  | paid | 1  |firstEventGuest | 1 | firstEventSponsor

這是重複事件的客人，活動的贊助紀錄行我想要得到的結果集是這樣的，如果可能

eventId | eventName | ticketId | type | guestId | guestName  | sponsorId  | sponsorName 
    1 | firstEvent | 1  | free | 1  |firstEventGuest | 1 | firstEventSponsor 
    1 | firstEvent | 2  | paid | NULL  |NULL  | NULL | NULL

我是我使用了錯誤的方法，或者它是默認的，請幫助我堅持這個挑戰/

來源

2017-08-27 Mike P Araya

第二排，你的票ID是2，但該類型的報酬？ –

是啊，那正確的，但來賓ID和贊助商標識的代表，我認爲這可能是默認的行爲。如果它是任何解決方法？ –

你的客桌應該有票的ID，以確定客戶有哪些門票。 –

這將適用於您的示例數據。

SELECT e.event_id AS 'eventId', 
     e.name AS 'eventName', 
     t.ticket_id AS 'ticketId', 
     t.type AS 'ticketType', 
     g.guest_id AS 'guestId', 
     CONCAT(g.first_name, " ", g.last_name) AS 'guestName', 
     s.sponsor_id AS 'sponsorId', 
     s.name AS 'sponsorName' 
    FROM t_event e 
    LEFT OUTER JOIN t_ticket t 
    ON e.event_id = t.event_id 
    LEFT OUTER JOIN (SELECT *, CASE WHEN event_id = 1 THEN 1 ELSE event_id END ticket_id FROM t_guest) g 
    ON t.event_id = g.event_id AND t.ticket_id = g.ticket_id 
    LEFT OUTER JOIN t_sponsor s 
    ON g.event_id = s.event_id 
WHERE e.event_id = 1 
GROUP BY e.event_id, t.ticket_id, g.guest_id, s.sponsor_id;

結果（我已經添加了來賓ID 3樣本數據）

eventId eventName ticketId ticketType guestId guestName   sponsorId sponsorName 
1  firstEvent 1  free  1  firstEvent guest 1   firstEventSponsor 
1  firstEvent 1  free  3  thirdEvent guest 1   firstEventSponsor 
1  firstEvent 3  paid  NULL NULL    NULL  NULL 
2  secondEvent 2  secondEvent 2  secondEvent guest 2   secondEventSponsor

來源

2017-08-27 20:33:52

對不起，但他們仍然票1和發起人1重複事件ID 1.我想要的是在重複值的地方爲空。我認爲它的死衚衕 –

正如我所說的，我添加了來賓ID 3樣本數據，它與事件ID 1相關聯。嘗試查詢到您的數據庫並查看結果。 –

如何獲得不同價值的每個表聯接

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