0
這是我現有的代碼。我可以使用一些關於如何優化的指導。實質上,我不想多次運行SQL查詢 - self.active_item?(r)。我在想,我可以做的,而不是做單獨的數據庫查詢,是檢索所有用戶的活動庫存項目(例如,self.active_inventory_items)的數組,然後將其轉換爲項目數組,然後查詢數組,以查看是否related_item ==項目。你怎麼看?重構我的代碼以消除單獨的數據庫查詢
# User has many inventory_items.
# Item has many inventory_items.
# InventoryItem belongs to user, item.
# in User Model
def retrieve_owned_items(purchasing_item)
related_items = purchasing_item.related_items # returns an array of Items (related to item user is going to purchase)
owned_items = []
unless related_items.nil?
related_items.each do |r| # iterate through each related item
if self.active_item?(r) then # runs a SQL query every time to check if the related item is currently an active item in the inventory
owned_items << InventoryItem.find_by_item_id(r.id) # create an array of related_items already owned
end
end
end
return (owned_items.blank? ? nil : owned_items)
end