Symfony3 Guard和登錄表單

Question

我嘗試使用Guard來創建登錄表單而不是security.yml方式。

Getuser和checkcredential都可以。
onAuthenticationSuccess是好的（如果我把onOuth​​enticationSuccess中的dump($token); die;我可以在令牌中看到我的用戶）並重定向到/ accueil。
但是，當它到達/ accueil它發回/登錄，因爲用戶身份驗證始終是匿名的！

不可能找到一個解決方案：C/

防火牆在security.yml：

firewalls: 
    dev: 
     pattern: ^/(_(profiler|wdt)|css|images|js)/ 
     security: false 

    login_firewall: 
     pattern: ^/login$ 
     anonymous: true 

    main: 
     pattern: ^/ 
     anonymous: ~ 
     logout: ~ 
     switch_user: true 
     guard: 
      provider: database 
      authenticators: 
       - ent.login_authenticator 

access_control: 
    - { path: ^/login$, roles: IS_AUTHENTICATED_ANONYMOUSLY } 
    - { path: ^/admin/, roles: ROLE_ADMIN } 
    - { path: ^/, roles: ROLE_USER } 

securityController

/** 
* @Route("/login", name="login") 
* 
*/ 
public function loginAction(Request $request) 
{ 

    if ($this->get('security.authorization_checker')->isGranted('IS_AUTHENTICATED_REMEMBERED')) { 
    return $this->redirectToRoute('accueil'); 
    } 

    $authenticationUtils = $this->get('security.authentication_utils'); 

    $exception = $authenticationUtils->getLastAuthenticationError(); 

    $lastUsername = $authenticationUtils->getLastUsername(); 

    return $this->render('EntBundle::login.html.twig', [ 
    'last_username' => $lastUsername, 
    'error' => $exception, 
    ]); 

} 

/** 
* @Route("/login_check", name="login_check") 
*/ 
public function loginCheckAction() 
{ 
    // this controller will not be executed, 
    // as the route is handled by the Security system 
} 

loginAuthenticator：

public function __construct(RouterInterface $router, UserPasswordEncoder $passwordEncoder, EntityManager $em) { 
$this->router = $router; 
$this->passwordEncoder = $passwordEncoder; 
    $this->em = $em; 
} 

public function getCredentials(Request $request) 
{ 
    if ($request->getPathInfo() != '/login_check') { 
     return null; 
    } 

    $request->getSession()->set(Security::LAST_USERNAME, $request->request->get('_username')); 

    return array(
     'username' => $request->request->get('_username'), 
     'password' => $request->request->get('_password'), 
); 
} 

public function getUser($credentials, UserProviderInterface $userProvider) 
{ 
    try { 
     return $this->em->getRepository('EntBundle:User\User')->findOneBy(array('username' => $credentials)); 
    } 
    catch (UsernameNotFoundException $e) { 
     throw new CustomUserMessageAuthenticationException($this->failMessage); 
    } 
} 

public function checkCredentials($credentials, UserInterface $user) { 

    $plainPassword = $credentials['password']; 
    if ($this->passwordEncoder->isPasswordValid($user, $plainPassword)) { 
     return true; 
    } 

    throw new CustomUserMessageAuthenticationException($this->failMessage); 
} 

public function onAuthenticationSuccess(Request $request, TokenInterface $token, $providerKey) 
{ 
    //  dump($token); die; 
    $url = $this->router->generate('accueil'); 
    return new RedirectResponse($url); 
} 

public function onAuthenticationFailure(Request $request, AuthenticationException $exception) 
{ 
    $request->getSession()->set(Security::AUTHENTICATION_ERROR, $exception); 

    $url = $this->router->generate('login'); 
    return new RedirectResponse($url); 
} 

public function start(Request $request, AuthenticationException $authException = null) 
{ 
    $url = $this->router->generate('login'); 
    return new RedirectResponse($url); 
} 

Answer 1

遺憾的緯度響應E，該代碼段會是這個樣子設置在symfony3應用程序令牌：

use Symfony\Component\Security\Core\Authentication\Token\UsernamePasswordToken; 
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Security; 
use Symfony\Component\Security\Http\Event\InteractiveLoginEvent; 

and the actual setting of the token part will be like: 
$token = new UsernamePasswordToken($user, $user->getPassword(), "firewall goes here for example: main", $user->getRoles()); 
$this->get("security.token_storage")->setToken($token); 

我希望我幫你這個:)