如何隨機生成一個關卡？

Question

我目前硬編碼像下面的代碼10個不同的實例，但但我想創造更多。我不知道是否有爲每個塊生成一個隨機的X值（這將是多大的水平）。一個10萬像素寬的水平將足夠好，但如果有人知道一個系統使水平繼續下去，我也想知道這一點。這基本上是我現在如何定義一個塊（除去不相干碼）：

block = new Block(R.drawable.block, 400, platformheight); 
block2 = new Block(R.drawable.block, 600, platformheight); 
block3 = new Block(R.drawable.block, 750, platformheight); 

的400是X位置，我想要通過電平隨機地放置，所述platformheight變量定義的Y位置，其我不想改變。

Answer 1

考慮到每一個塊需要比前一個進一步

List<Block> blocks = new LinkedList<Block>(); 
Random rnd = new Random(System.currentTimeMillis()); 

int x = 400; 

while (youNeedMoreBlocks) 
{ 
    int offset = rnd.nextInt(400) + 100; //500 is the maximum offset, this is a constant 
    x += offset;       //ofset will be between 100 and 400 

    blocks.add(new Block(R.drawable.block, x, platformheight)); 

    //if you have enough blocks, set youNeedMoreBlocks to false 
} 

但是這看起來過於簡單化了我。要麼我不明白你的問題，要麼就是那麼簡單。

編輯：

對於這樣的任務：

block.setY(three_quarters - 10); 
block2.setY(three_quarters - 10); 
block3.setY(three_quarters - 10); 

您需要修改與循環：

List<Block> blocks = new LinkedList<Block>(); 
Random rnd = new Random(System.currentTimeMillis()); 

int x = 400; 

while (youNeedMoreBlocks) 
{ 
    int offset = rnd.nextInt(400) + 100; //500 is the maximum offset, this is a constant 
    x += offset;       //ofset will be between 100 and 400 

    Block tmp = new Block(R.drawable.block, x, platformheight); 
    tmp.setY(three_quarters - 10);     
      //do with tmp everything you need to apply to each block 

    blocks.add(tmp); 

    //if you have enough blocks, set youNeedMoreBlocks to false 
} 

另一種明智的想法是，當產生對需求的塊球員接近地圖的邊緣，所以你有更快的加載時間。