下面的代碼是好的上傳文本文件,但它不能上傳JPEG文件(不完全 - 文件名是好的,但圖像被損壞):上傳在C#中使用FTP編碼文件
private void up(string sourceFile, string targetFile)
{
try
{
string ftpServerIP = ConfigurationManager.AppSettings["ftpIP"];
string ftpUserID = ConfigurationManager.AppSettings["ftpUser"];
string ftpPassword = ConfigurationManager.AppSettings["ftpPass"];
//string ftpURI = "";
string filename = "ftp://" + ftpServerIP + "//" + targetFile;
FtpWebRequest ftpReq = (FtpWebRequest)WebRequest.Create(filename);
ftpReq.Method = WebRequestMethods.Ftp.UploadFile;
ftpReq.Credentials = new NetworkCredential(ftpUserID, ftpPassword);
StreamReader stream = new StreamReader(sourceFile);
Byte[] b = System.Text.Encoding.UTF8.GetBytes(stream.ReadToEnd());
stream.Close();
ftpReq.ContentLength = b.Length;
Stream s = ftpReq.GetRequestStream();
s.Write(b, 0, b.Length);
s.Close();
System.Net.FtpWebResponse ftpResp = (FtpWebResponse)ftpReq.GetResponse();
MessageBox.Show(ftpResp.StatusDescription);
}
catch (Exception ex)
{
MessageBox.Show(ex.ToString());
}
}
我有另一種解決方案,可以上傳文件:
private void Upload(string sourceFile, string targetFile)
{
string ftpUserID;
string ftpPassword;
string ftpServerIP;
ftpServerIP = ConfigurationManager.AppSettings["ftpIP"];
ftpUserID = ConfigurationManager.AppSettings["ftpUser"];
ftpPassword = ConfigurationManager.AppSettings["ftpPass"];
FileInfo fileInf = new FileInfo(sourceFile);
FtpWebRequest reqFTP;
// Create FtpWebRequest object from the Uri provided
reqFTP = (FtpWebRequest)(FtpWebRequest.Create(new Uri("ftp://" + ftpServerIP + "//" + targetFile)));
// Provide the WebPermission Credintials
reqFTP.Credentials = new NetworkCredential(ftpUserID, ftpPassword);
// Bypass default lan settings
reqFTP.Proxy = null;
// By default KeepAlive is true, where the control connection is not closed
// after a command is executed.
reqFTP.KeepAlive = false;
// Specify the command to be executed.
reqFTP.Method = WebRequestMethods.Ftp.UploadFile;
// Specify the data transfer type.
reqFTP.UseBinary = true;
// Notify the server about the size of the uploaded file
reqFTP.ContentLength = fileInf.Length;
// The buffer size is set to 2kb
int buffLength = 2048;
Byte[] buff;
buff = new byte[buffLength];
int contentLen;
// Opens a file stream (System.IO.FileStream) to read the file to be uploaded
FileStream fs = fileInf.OpenRead();
try
{
// Stream to which the file to be upload is written
Stream strm = reqFTP.GetRequestStream();
// Read from the file stream 2kb at a time
long filesize = fs.Length;
int i=0;
contentLen = fs.Read(buff, 0, buffLength);
// Till Stream content ends
while (contentLen != 0)
{
Application.DoEvents();
// Write Content from the file stream to the FTP Upload Stream
strm.Write(buff, 0, contentLen);
contentLen = fs.Read(buff, 0, buffLength);
i = i + 1;
//Double percentComp = (i * buffLength) * 100/filesize;
//ProgressBar1.Value = (int)percentComp;
}
// Close the file stream and the Request Stream
strm.Close();
fs.Close();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message, "Upload Error");
}
}
但在這裏我有相反的問題 - 畫面是好的,但文件名被破壞。
我知道那是因爲編碼的,但我不知道如何使字節數組具有所需的編碼...
我不明白,爲什麼你會有第二個代碼損壞的文件名的問題,但與第一個代碼沒有關係。爲什麼接受的答案會對此有所幫助。在所有情況下,您都以完全相同的方式指定文件名。 – 2017-10-25 06:51:20
對不起馬丁。我十年前寫過這個問題。我不記得是什麼問題和解決方案。我想你應該用自己的問題開一個新的主題。 – Asaf 2017-10-25 07:01:54
我沒有問題,我只是想知道你的問題和答案是什麼:) – 2017-10-25 07:16:09