2010-12-07 73 views

回答

2

urlparse.parse_qs:http://docs.python.org/library/urlparse.html#urlparse.parse_qs

如果您使用的是2.6年長的Python,這個函數的先前的位置是CGI模塊:http://docs.python.org/library/cgi.html#cgi.parse_qs

+0

問題是... >>>進口 裏urlparse >>>目錄(裏urlparse) [ 'BaseResult',「MAX_CACHE_SIZE ','ParseResult','SplitResult','__all__','__builtins__','__doc__','__file__','__name__','_parse_cache','_splitnetloc','_splitparams','clear_cache','non_hierarchical', 'scheme_chars','test','test_input','urldefrag','urljoin','urlparse','urlsplit','urlunparse','urlunsplit','uses_fragment','uses_netloc','uses_params','uses_query ','uses_relative'] – vkris 2010-12-07 22:55:20

1

如果您正在使用Python 2.6 <

parse_qscgi模塊

在它仍然有2.7的向後兼容性