Java通知並等待異常？

Question

我正在嘗試編寫程序以瞭解有關Java線程的更多信息。程序的邏輯很簡單，當TimeCount類的count變量等於5時，第一個線程將運行。

這是傳統的等待和通知問題。我不知道代碼中的錯誤在哪裏？請幫忙。

public class TestThread { 

    public static void sleep(int time) { 
     try { 
      Thread.currentThread().sleep(time); 
     } catch (InterruptedException ex) { 
      ex.printStackTrace(); 
     } 
    } 

    public static void main(String[] args) { 

     final MyTimeCount myTimeCount = new MyTimeCount(); 
     final ReentrantLock myLock = new ReentrantLock(); 
     final Condition cvar = myLock.newCondition(); 

     Thread t1 = new Thread(new Runnable() { 
      @Override 
      public void run() { 
       myLock.lock(); 
       try { 
        while (myTimeCount.getCount() >= 5) { 
         cvar.await(); 
        } 
        System.out.println("--- data is ready, so we can go --- "); 

       } catch (Exception ex) { 
        ex.printStackTrace(); 
       } finally { 
        myLock.unlock(); 
       }    
      } 
     }); 

     Thread t3 = new Thread(new Runnable() { 
      @Override 
      public void run() { 
       while (true) { 
        int count = myTimeCount.increase(); 
        if (count == 5) { 
         cvar.signalAll(); 
         break; 
        } 

        sleep(6000); 
       } 
      } 
     }); 

     //----------- 
     t1.start();  
     t3.start(); 
    } 
} 

class MyTimeCount { 
    int count; 

    public int increase() { 
     count++; 
     System.out.println("time increase count=" + count); 
     return count; 
    } 

    public int decrease() { 
     count--; 
     System.out.println("time decrease count=" + count); 
     return count; 
    } 

    public int getCount() { 
     return count; 
    } 
} 

Answer 1

你while while循環。條件應該是myTimeCount.getCount() < 5