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我有以下腳本調用該查詢數據庫和輸出結果作爲電子郵件。但是,我想單獨發送結果(10個結果= 10封電子郵件),而不是在一封包含所有結果的電子郵件中。電子郵件的個人結果(10結果= 10電子郵件),而不是1電子郵件與其中的所有數據
任何一種靈魂都可以指向正確的方向嗎?這就是我現在所擁有的。我應該對結果進行預測嗎?
<?php
//authentication for database
$hostname = "xxxx";
$username = "xxxx";
$password = "xxxx";
//connection to the database
$dbhandle = mysql_connect($hostname, $username, $password)
or die("Unable to connect to MySQL");
//select a database to work with
$selected = mysql_select_db("test",$dbhandle)
or die("Could not select examples");
//execute the SQL query and return records
$result = mysql_query("SELECT * FROM tbl_assignees WHERE work_pass_expiry = DATE(NOW())");
if (!$result) {
//handle your error
die('The query failed.');
}
//variable for email message
$to = 'some email address';
$emailBody = "";
//fetch tha data from the database
while ($row = mysql_fetch_array($result))
{
$subject = $row['name']."'s"." work pass is expiry soon";
$emailBody .="Creator: ".$row['rlog_create_user_name']." \n";
$emailBody .="Company: ".$row['company']."\n";
$emailBody .="Assignee's Name: ".$row['name']." \n";
$emailBody .="Fin No: ".$row['fin_no_']." \n";
$emailBody .="Relationship: ".$row['relationship']." \n";
$emailBody .="Main Holder's Fin :".$row['main_holder_fin']." \n";
$emailBody .="Work Pass Type :".$row['work_pass_type']." \n";
$emailBody .="Work Pass Expiry :".$row['work_pass_expiry']." \n";
$emailBody .="Passport No. :".$row['passport_no_']." \n";
$emailBody .="Passport Expiry :".$row['passport_expiry']." \n";
$emailBody .="D.O.B :".$row['d_o_b']." \n";
$emailBody .="Contact :".$row['contact']." \n";
$emailBody .="Email :".$row['email']." \n";
$emailBody .="Notes :".$row['note'];
}
$headers = 'From: Work Pass Notification System <[email protected]>' . "\r\n" .
'Reply-To: someemailaddress' . "\r\n" .
'X-Mailer: PHP/' . phpversion();
if(mail($to, $subject, $emailBody, $headers)) {
echo $emailBody;
echo 'Email sent successfully!';
} else {
echo $emailBody;
die('Failure: Email was not sent!');
}
//close the connection
mysql_close($dbhandle);
?>
我試過了,它確實發出了2封電子郵件,滿分爲2個匹配結果。 但是,現在電子郵件以以下格式發送,第一封電子郵件包含A,第二封電子郵件包含A + B。 如何確保電子郵件內容未添加到下一封電子郵件中,即第一封電子郵件包含只有第二封電子郵件只包含B? 我很接近完成這個,真的需要指導。 請指教。 謝謝 – 2013-03-27 09:54:46
正如我所提到的,在向其添加內容之前,您必須在循環中使用$ emailBody =「」每次清除$ emailBody內容。這將確保以前的郵件內容不會被添加到下一個。 – 2013-03-27 12:15:43