如果A0通過a4已經是列表...你只需要把他們全部放入一個大列表。
讓我知道這對你的作品:
a0 = [str(x) for x in range(10)]
a1 = [str(x) for x in range(10, 20)]
a2 = [str(x) for x in range(20, 30)]
a3 = [str(x) for x in range(30, 40)]
a4 = [str(x) for x in range(40, 50)]
print("a0: {}".format(", ".join(a0)))
print("a1: {}".format(", ".join(a1)))
print("a2: {}".format(", ".join(a2)))
print("a3: {}".format(", ".join(a3)))
print("a4: {}".format(", ".join(a4)))
matrix = [
a0,
a1,
a2,
a3,
a4
]
# Below is another way:
# matrix = []
# matrix.append(a0)
# matrix.append(a1)
# matrix.append(a2)
# matrix.append(a3)
# matrix.append(a4)
print("matrix[3][4]: {}".format(matrix[3][4]))
輸出:
a0: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
a1: 10, 11, 12, 13, 14, 15, 16, 17, 18, 19
a2: 20, 21, 22, 23, 24, 25, 26, 27, 28, 29
a3: 30, 31, 32, 33, 34, 35, 36, 37, 38, 39
a4: 40, 41, 42, 43, 44, 45, 46, 47, 48, 49
matrix[3][4]: 34
完美,這是這麼多比循環更好! – JDizzle