檢查收到的原始HTTP消息

Question

我正在開發一個Android應用程序並向我的IIS服務器發送multipart-form-data HTTP POST。我需要看到我的服務器正在接收的原始HTTP消息。爲此，在Visual Studio 2013，我把一箇中斷只是這一行

public String Report([Bind(Include = "lasfotos,comentario,asunto")] HttpPostedFileBase lasfotos, string comentario, string asunto) 

在局部變量，我可以看到很多有關類似路徑的HTTP消息，內容lenght等，但這一>基地>要求后里面我無法找到原始HTTP的位置。

編輯：我爲什麼認爲看到原始http是一個解決方案？因爲我可以很容易地在這裏找到我的問題。但我會告訴你我的基本問題： 我有這個功能在Java中發送的數據到服務器。我可以看到「comentario」和「asunto」，而是「lasfotos」 =空

public static String Postear(ArrayList<File> files, String asunto, String detalle) 
{ 
    String respuesta; 
    try 
    { 
     String boundary = "qu1ckr3port_myb0undy"; 
     String filesboundary = "boundy_4_files"; 
     URL url = new URL("http://192.168.10.100/QuickReport/Uploads/Report"); 
     HttpURLConnection connection = (HttpURLConnection) url.openConnection(); 
     connection.setDoInput(true); 
     connection.setDoOutput(true); 
     connection.setUseCaches(false); 
     connection.setRequestMethod("POST"); 
     connection.setRequestProperty("Connection", "Keep-Alive"); 
     connection.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary); 
     DataOutputStream outputStream = new DataOutputStream(connection.getOutputStream()); 
     outputStream.writeBytes("--"+boundary+"\r\n" + 
       "Content-Disposition: form-data; name=\"lasfotos\"\r\n" + 
       "Content-Type: multipart/mixed; boundary="+filesboundary+"\r\n\r\n"); 
     for (byte i = 0; i < files.size(); i++) 
     { 
      outputStream.writeBytes("--"+filesboundary+"\r\n" + 
        "Content-Disposition: file; filename=\"" + files.get(i).getName() + "\"\r\n" + 
        "Content-Type: image/jpeg\r\n\r\n"); 
      FileInputStream fileInputStream = new FileInputStream(files.get(i)); 
      int bytesAvailable = fileInputStream.available(); 
      int bufferSize = Math.min(bytesAvailable, 1024 * 1024); 
      byte[] buffer = new byte[bufferSize]; 
      int bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
      while (bytesRead > 0) 
      { 
       outputStream.write(buffer, 0, bufferSize); 
       bytesAvailable = fileInputStream.available(); 
       bufferSize = Math.min(bytesAvailable, 1024 * 1024); 
       bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
      } 
      fileInputStream.close(); 
      outputStream.writeBytes("\r\n"); 
     } 
     outputStream.writeBytes("--"+filesboundary+"--\r\n" + 
       "--"+boundary+"\r\n" + 
       "Content-Disposition: form-data; name=\"comentario\"\r\n\r\n" + 
       detalle + "\r\n" + 
       "--"+boundary+"\r\n"); 
     outputStream.writeBytes("\r\n" + 
       "--"+boundary+"\r\n" + 
       "Content-Disposition: form-data; name=\"asunto\"\r\n\r\n" + 
       asunto + "\r\n" + 
       "--"+boundary+"--\r\n"); 
     respuesta = ""; 
     String linea; 
     BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream())); 
     while ((linea = reader.readLine()) != null) respuesta += linea; 
     reader.close(); 
     outputStream.flush(); 
     outputStream.close(); 
    } catch (Exception e) 
    { 
     respuesta = "error"; 
     e.printStackTrace(); 
    } 
    return respuesta; 
} 

Answer 1

問題是壞的文件，我認爲我的變量值（服務器）。我也跟着在本頁面http://www.w3.org/TR/html401/interact/forms.html#h-17.13.4.2

Content-Type: multipart/form-data; boundary=AaB03x 

--AaB03x 
Content-Disposition: form-data; name="submit-name" 

Larry 
--AaB03x 
Content-Disposition: form-data; name="files" 
Content-Type: multipart/mixed; boundary=BbC04y 

--BbC04y 
Content-Disposition: file; filename="file1.txt" 
Content-Type: text/plain 

... contents of file1.txt ... 
--BbC04y 
Content-Disposition: file; filename="file2.gif" 
Content-Type: image/gif 
Content-Transfer-Encoding: binary 

...contents of file2.gif... 
--BbC04y-- 
--AaB03x-- 

記錄格式，那就是這個問題。我只是改變了我的代碼，現在正在完美工作。這裏是我的新代碼：

public static String Postear(ArrayList<File> files, String asunto, String detalle) 
{ 
    String respuesta; 
    try 
    { 
     String boundary = "qu1ckr3port_myb0undy"; 
     URL url = new URL("http://192.168.10.100/QuickReport/Uploads/Report"); 
     HttpURLConnection connection = (HttpURLConnection) url.openConnection(); 
     connection.setDoInput(true); 
     connection.setDoOutput(true); 
     connection.setUseCaches(false); 
     connection.setRequestMethod("POST"); 
     connection.setRequestProperty("Connection", "Keep-Alive"); 
     connection.setRequestProperty("Content-Type", "multipart/form-data;boundary=" + boundary); 
     DataOutputStream outputStream = new DataOutputStream(connection.getOutputStream()); 
     for (byte i = 0; i < files.size(); i++) 
     { 
      outputStream.writeBytes("--"+boundary+"\r\n" + 
        "Content-Disposition: form-data; name=\"lasfotos\" filename=\"" + files.get(i).getName() + "\"\r\n" + 
        "Content-Type: image/jpeg\r\n\r\n"); 
      FileInputStream fileInputStream = new FileInputStream(files.get(i)); 
      int bytesAvailable = fileInputStream.available(); 
      int bufferSize = Math.min(bytesAvailable, 1024 * 1024); 
      byte[] buffer = new byte[bufferSize]; 
      int bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
      while (bytesRead > 0) 
      { 
       outputStream.write(buffer, 0, bufferSize); 
       bytesAvailable = fileInputStream.available(); 
       bufferSize = Math.min(bytesAvailable, 1024 * 1024); 
       bytesRead = fileInputStream.read(buffer, 0, bufferSize); 
      } 
      fileInputStream.close(); 
      outputStream.writeBytes("\r\n"); 
     } 
     outputStream.writeBytes("--"+boundary+"\r\n" + 
       "Content-Disposition: form-data; name=\"comentario\"\r\n\r\n" + 
       detalle + "\r\n"); 
     outputStream.writeBytes("\r\n" + 
       "--"+boundary+"\r\n" + 
       "Content-Disposition: form-data; name=\"asunto\"\r\n\r\n" + 
       asunto + "\r\n" + 
       "--"+boundary+"--\r\n"); 
     respuesta = ""; 
     String linea; 
     BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream())); 
     while ((linea = reader.readLine()) != null) respuesta += linea; 
     reader.close(); 
     outputStream.flush(); 
     outputStream.close(); 
    } catch (Exception e) 
    { 
     respuesta = "error"; 
     e.printStackTrace(); 
    } 
    return respuesta; 
} 

希望這是有用的人......