如何從不同數組中的相同鍵獲取數據解析iOS？

Question

我是新手到Parse.com我嘗試用相同的密鑰，但值來從解析表中的數據是一樣的

-(void)getdata 
{ 
NSMutableArray *allObjects = [NSMutableArray array]; 
NSUInteger limit = 1000; 
__block NSUInteger skip = 0; 
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"]; 
[query whereKey:@"Type" containedIn:@[@"Temporary", @"Business"]]; 
[query setLimit: limit]; 
[query setSkip: skip]; 
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) { 
    if (!error) { 
     [allObjects addObjectsFromArray:objects]; 
     if (objects.count == limit) { 

      skip += limit; 
      [query setSkip: skip]; 
      [query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) { 
       [allObjects addObjectsFromArray:objects]; 
       self.qpinname=[allObjects valueForKey:@"GPIN"]; 
       NSLog(@"Qpin Array %lu",(unsigned long)[self.qpinname count]); 
       self.locationArray=[allObjects valueForKey:@"Location"]; 
       self.latitude=[self.locationArray valueForKey:@"lat"]; 
       self.longitude=[self.locationArray valueForKey:@"lng"]; 
       self.address=[allObjects valueForKey:@"Address"]; 
       self.usernameArray=[allObjects valueForKey:@"AddedBy"]; 
       [self getdata2]; 
       hudView.hidden=TRUE; 
      }]; 
      } 
      } 
    else 
    { 
       NSLog(@"Error: %@ %@", error, [error userInfo]); 
      } 
      }]; 
} 
-(void)getdata2 
{ 
NSMutableArray *allObjects = [NSMutableArray array]; 
NSUInteger limit = 1000; 
__block NSUInteger skip = 0; 
PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"]; 
[query whereKey:@"Type" equalTo:@"Personal"]; 
[query setLimit: limit]; 
[query setSkip: skip]; 
[query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) { 
    if (!error) { 
     [allObjects addObjectsFromArray:objects]; 
     if (objects.count == limit) { 

      skip += limit; 
      [query setSkip: skip]; 
      [query findObjectsInBackgroundWithBlock:^(NSArray *objects, NSError *error) { 
       [allObjects addObjectsFromArray:objects]; 
       self.lqpinname=[allObjects valueForKey:@"GPIN"]; 
       NSLog(@"Qpin Array %lu",(unsigned long)[self.lqpinname count]); 
       self.llocationArray=[allObjects valueForKey:@"Location"]; 
       self.llatitude=[self.llocationArray valueForKey:@"lat"]; 
       self.llongitude=[self.llocationArray valueForKey:@"lng"]; 
       self.laddress=[allObjects valueForKey:@"Address"]; 
       self.usernameArray=[allObjects valueForKey:@"AddedBy"]; 
      }]; 
     } 
    } 
    else 
    { 
     NSLog(@"Error: %@ %@", error, [error userInfo]); 
    } 
}]; 
} 

在這裏，我要爲同一個密鑰，但不同的數組中獲取數據不同，但它是不爲我工作，請給我解決方案。

謝謝。

Answer 1

我不知道這是否是你想要做什麼，但：

PFQuery *query = [PFQuery queryWithClassName:@"MapInfo"]; 
    [query whereKey:@"Type" containedIn:@[@"Temporary", @"Business", @"Personal"]]; 

    [query findObjectsInBackgroundWithBlock:^(NSArray *result, NSError *error) { 

     if (!error && result.count) 
     { 
      for (PFObject *parseResponse in result) 
      { 
       if ([[parseResponse objectForKey:@"Type"] isEqual:@"Personal"]) 
       { 
        //the logic for data with Type = Personal 
       } 
       else 
       { 
        //the logic for the data with other Types 
       } 
      } 
     } 
     else 
     { 
      NSLog(@"Error: %@ %@", error, [error userInfo]); 
     } 
    }];