命名文件順序

Question

我有一堆用文件夾中的隨機文件名的文件，而我想他們相繼更名爲Sample1_1，Sample1_2，Sample2_1，Sample2_2，Sample3_1，Sample3_2等等...

我迄今爲止代碼：

%%reading files in the directory and renaming it 

files = dir('*.NEF'); 

for i = 1:name1(files) 
    for j = 1:2 
     filename = files(i).name; 
     I = imread(filename); 
     imwrite(I,sprintf('Sample%d_%d.NEF',i,j)); 
     delete(filename); 
    end 
end 

Answer 1

確定這裏是一個簡單的代碼產生你想要的名稱。爲了簡化，我創建了2個數組，每個數組包含我們想要放入文件名的數字。然後很容易遍歷數組並獲取正確的數字。這是很容易實現你的應用程序：

clear 
clc 

%// In my example I generate only 8 names 
NumSamples = 4; 

CheckSample = kron(1:NumSamples,ones(1,2)); 
OneOrTwo = repmat([1 2],1,NumSamples); 

CheckSample和OneOrTwo是2個陣列我指的是。您可以看到對應關係以創建具有適當數字的文件名。

CheckSample = 

    1  1  2  2  3  3  4  4 


OneOrTwo = 

    1  2  1  2  1  2  1  2 

%// For demonstration purposes, create a cell array containing the filenames. 
NameCell = cell(1,NumSamples*2); 

%/ Now loop through each image (in your case) to generate the file name. 

for k = 1:2*NumSamples 

     NameCell{k} = sprintf('Sample%d_%d',CheckSample(k),OneOrTwo(k)); 

end 

NameCell 

NameCell看起來是這樣的：

NameCell = 

    Columns 1 through 4 

    'Sample1_1' 'Sample1_2' 'Sample2_1' 'Sample2_2' 

    Columns 5 through 8 

    'Sample3_1' 'Sample3_2' 'Sample4_1' 'Sample4_2' 

從你上面的代碼，你可以做這樣的事情：

files = dir('*.NEF'); 
    NumSamples = length(files)/2; 

    CheckSample = kron(1:NumSamples,ones(1,2)); 
    OneOrTwo = repmat([1 2],1,NumSamples); 

for k = 1:2*NumSamples 

    filename = files(k).name; 
    I = imread(filename); 

    CurrentName = sprintf('Sample%d_%d',CheckSample(k),OneOrTwo(k)); 
    CurrentName = strcat(CurrentName,'.NEF'); %// Keep right file extension. 

    imwrite(I,CurrentName); 

end