我有一個標量值如何將SQL Server中的單詞聚合在一起？
八萬七千九百八十九
我怎樣才能使它七八十一千九百八十九
到目前爲止，我已經能夠找到發生的位置，但之後我迷路了
with cte as
(select 'Eighty Thousand and Seven Thousand and Nine Hundred and Eighty Nine' as name
),
pos as
(select patindex('%Thousand%',name) pos, name from cte
union all
select pos+patindex('%Thousand%',substring(name, pos+1, len(name))) pos, name from pos
where patindex('%Thousand%',substring(name, pos+1, len(name)))>0
)
select pos from pos
提前致謝。
Declare @String1 varchar(100) Declare @String2 varchar(100) declare @string nvarchar(264)
set @string = N'Eighty Thousand and Seven Thousand and Nine Hundred and Eighty Nine';
-- Ensure it ends with a space
SET @string = @string + ' ';
WITH cte (Id, Value, Rest)
AS (SELECT 1 as Id,SUBSTRING(@string, 1, CHARINDEX(' ', @string, 1) - 1) AS Value ,SUBSTRING(@string, CHARINDEX(' ', @string, 1) + 1, LEN(@string)) AS Value
UNION ALL SELECT Id + 1 AS Id,SUBSTRING(Rest, 1, CHARINDEX(' ', Rest, 1) - 1) AS Value,SUBSTRING(Rest, CHARINDEX(' ', Rest, 1) + 1, LEN(Rest)) AS Value FROM cte WHERE CHARINDEX(' ', Rest, 1) <> 0)
SELECT @String1= Value
FROM cte
WHERE id = 2; -- = 2rd word to get
WITH cte1 (Id, Value, Rest)
AS (SELECT 1 as Id,SUBSTRING(@string, 1, CHARINDEX(' ', @string, 1) - 1) AS Value ,SUBSTRING(@string, CHARINDEX(' ', @string, 1) + 1, LEN(@string)) AS Value
UNION ALL SELECT Id + 1 AS Id,SUBSTRING(Rest, 1, CHARINDEX(' ', Rest, 1) - 1) AS Value,SUBSTRING(Rest, CHARINDEX(' ', Rest, 1) + 1, LEN(Rest)) AS Value FROM cte1 WHERE CHARINDEX(' ', Rest, 1) <> 0)
SELECT @String2 =Value
FROM cte1
WHERE id = 5; -- = 5rd word to get
IF @[email protected]
Begin set @string = Replace(Replace(@string,'Thousand and',''),' ',' ') Print @string
END
猜測：分裂的「和」，並轉換每一部分爲數字（八萬= 80000），再加入所有與結果轉換爲文本。雖然這將在「七八萬」上失效 - 780000） –
您可能會更好地將字符串解析爲整數值，然後將整數轉換爲您最喜歡的散文風格。您的單個示例可以在「和」處被分解並且每個片段被轉換和求和。 – HABO