來自其他文件的燒瓶路由器

Question

我現在正在像下面那樣構建Flask應用程序。

myserver 
- server.py 
- myapp 
-- urls.py 
-- models.py 
-- views.py 
-- consts.py 

而我的代碼在這裏。

server.py

from flask import Flask 
from flask_sqlalchemy import SQLAlchemy 

# Flask App 
application = Flask(__name__) 

# SQLAlchemy 
application.config['SQLALCHEMY_DATABASE_URI'] = "sqlite:./local.db" 
db = SQLAlchemy(application) 

if __name__ == "__main__": 
    application.run(debug=True) 

urls.py

from server import application 
from . import views 

@application.route('/') 
def version(): 
    return views.version() 

但是當我運行server.py和開放http://localhost:5000/服務器說：404 Not Found。

所以我搜索了stackoverflow，我發現了一些關於Blueprint的描述。我製作了一個名爲app的藍圖，如app = Blueprint('app', __name__)，並從server.py註冊它，但我得到了AttributeError: module 'urls' has no attribute 'app'。

如何在其他文件中定義url路由器？

Answer 1

這裏的例子是Blueprint。文件的結構：

/project_folder 
    server.py 
    urls.py 
    urls2.py 

server.py：

from flask import Flask 
from urls import urls_blueprint 
from urls2 import urls2_blueprint 


app = Flask(__name__) 
# register routes from urls 
app.register_blueprint(urls_blueprint) 
# we can register routes with specific prefix 
app.register_blueprint(urls2_blueprint, url_prefix='/urls2') 

if __name__ == "__main__": 
    app.run(debug=True) 

urls.py：

from flask import Blueprint 

urls_blueprint = Blueprint('urls', __name__,) 


@urls_blueprint.route('/') 
def index(): 
    return 'urls index route' 

urls2.py：

from flask import Blueprint 
urls2_blueprint = Blueprint('urls2', __name__,) 


@urls2_blueprint.route('/') 
def index(): 
    return 'urls2 index route' 

運行服務器和開放http://localhost:5000/和http://localhost:5000/urls2/。

希望這會有所幫助。