使用Javascript - 如何訪問對象的成功塊

Question

我需要AJAX已經修改後的訪問對象之外，但是當我嘗試打印它，它會顯示一個空值

我怎樣才能解決這個問題？

$(document).ready(function(){ 
    var arrayLength = whatever...; 
    var myArray = []; 

    for (var i = 0; i < arrayLength; i++) { 

     $.ajax({ 
      myArray: myArray, 
      type: 'GET', 
      dataType: 'jsonp', 
      data: {}, 
      url: "https://api....", 
      error: function (jqXHR, textStatus, errorThrown) { 
       console.log(jqXHR) 
      }, 
      success: function (response) { 
       var name = response.data.name; 
       var url = response.data.url; 
       for(var x = 0; x < 5; x++) { 
        var pin = {name: name, url:url}; 
        myArray.push(pin); 
       } 
      }, 
      async: false 
     }); 
    } 

    // I want to print myArray here 
}); 

Answer 1

$(document).ready(function(){ 
    var arrayLength = whatever...; 
    var myArray = []; 

    for (var i = 0; i < arrayLength; i++) { 

     $.ajax({ 
      //myArray: myArray, 
      type: 'GET', 
      dataType: 'jsonp', 
      data: {}, 
      url: "https://api....", 
      error: function (jqXHR, textStatus, errorThrown) { 
       console.log(jqXHR) 
      }, 
      success: function (response) { 
       var name = response.data.name; 
       var url = response.data.url; 
       for(var x = 0; x < 5; x++) { 
        var pin = {name: name, url:url}; 
        //allPins.push(pin); 
        myArray.push(pin); 
       } 
      }, 
      async: false 
     }); 
    } 

    // I want to print myArray here 
});