這似乎很容易使用Spring Security下面的教程,但是當我嘗試做與此應用程序一樣,我可以得到它的工作(我必須承認,我的天堂」寫)。問題試圖使用Spring Security與我的jsp aplication
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現在在一些偉大的人的幫助下,我終於得到了應用程序要求用戶進行身份驗證,但現在我遇到了一個新問題:當我嘗試使用下列用戶之一訪問應用程序時(applicationContext- security.xml文件),我得到這個消息:
這裏的web.xml
代碼:
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>dispatcher</servlet-name>
<servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
<load-on-startup>2</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>dispatcher</servlet-name>
<url-pattern>*.htm</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>/WEB-INF/applicationContext-security.xml</param-value>
</context-param>
<welcome-file-list>
<welcome-file>redirect.jsp</welcome-file>
</welcome-file-list>
<error-page>
<error-code>403</error-code>
<location>/sinacceso.jsp</location>
</error-page>
</web-app>
context.xml中:
<?xml version="1.0" encoding="UTF-8"?>
<Context antiJARLocking="true" path="/Test01"/>
調度-servlet.xml中:
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">
<beans>
<!-- GENERALES -->
<bean id="viewResolver"
class="org.springframework.web.servlet.view.UrlBasedViewResolver">
<property name="viewClass"
value="org.springframework.web.servlet.view.tiles2.TilesView" />
</bean>
<bean id="tilesConfigurer"
class="org.springframework.web.servlet.view.tiles2.TilesConfigurer">
<property name="definitions">
<list>
<value>/WEB-INF/tiles.xml</value>
</list>
</property>
</bean>
<bean name="/index.htm" class="paginas.index"/>
<bean name="secure/villancicos.htm" class="paginas.villancicos"/>
<bean name="secure/administracion.htm" class="paginas.administracion"/>
</beans>
的applicationContext-security.xml文件:
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:p="http://www.springframework.org/schema/p"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<http>
<intercept-url pattern="/index.htm" filters="none" />
<intercept-url pattern="/secure/administracion.htm" access="ROLE_SUPERVISOR" />
<intercept-url pattern="/secure/**" access="ROLE_USER" />
<form-login />
<anonymous />
<http-basic />
<logout logout-success-url="/index.htm" />
</http>
<authentication-manager alias="myAuthenticationManager">
<authentication-provider>
<password-encoder hash="md5"/>
<user-service>
<user name="rod" password="a564de63c2d0da68cf47586ee05984d7" authorities="ROLE_SUPERVISOR, ROLE_USER, ROLE_TELLER" />
<user name="dianne" password="65d15fe9156f9c4bbffd98085992a44e" authorities="ROLE_USER,ROLE_TELLER" />
<user name="scott" password="2b58af6dddbd072ed27ffc86725d7d3a" authorities="ROLE_USER" />
<user name="peter" password="22b5c9accc6e1ba628cedc63a72d57f8" authorities="ROLE_USER" />
</user-service>
</authentication-provider>
</authentication-manager>
</beans:beans>
此應用程序正在使用Spring 2.5的帶彈簧安全2.0.4(從我一直在關注本教程的版本相同)。
看起來像您使用的版本3種模式:彈簧豆-3.0.xsd和彈簧安全3.0.xsd和 – Ritesh
@ Ritesh-,哪些我應該使用? :(原因我已經嘗試過spring-beans-2.0.xsd和spring-security-2.0.1.xsd,但是我一直得到相同的錯誤:( – eddy
那麼,如果你使用的是Spring 2.5,那麼它應該是spring -beans-2.5.xsd。spring-security-2.0.4.xsd應該和spring-security-2.0.4一起使用。還有,你是否看到任何日誌文件中的錯誤堆棧? – Ritesh