1
從我收集了這些如果AS在SQL中作爲別名工作,那麼它不應該在函數中工作嗎?
SELECT
people.id,
people.name,
COUNT(sales.sale) AS sale_count,
RANK() OVER (ORDER BY sale_rank DESC) AS sale_rank
FROM people
JOIN sales ON people.id = sales.people_id
GROUP BY people.id
ORDER BY sale_count DESC;
應該意味着COUNT(sales.sale)
相同sale_count
但如果我用 RANK() OVER (ORDER BY COUNT(sales.sale) DESC) AS sale_rank
請問這是怎麼一如既往工程或會是這樣,因爲示例只能我正在做Codewars上的「SQL基礎:簡單JOIN和RANK」kata?