jqGrid：格式化程序：「actions」不適用於遠程json url

Question

我試圖使用jqGrid格式化程序：遠程json url的「actions」，但它會移動行，因爲列名和實際返回的數據數不匹配行列在列名中是多餘的）。我在線搜索，它看起來像所有的例子是本地數據（在頁面上），其中json用作鍵/值，而url：somepage.php返回一列csv種類的格式（沒有鍵，只是值） 。我也使用id作爲隱藏字段，而所有示例都顯示id。我還使用了一個隱藏列。 這裏是我的colmodel：

url: "manager_json", 
       editurl: "manager_edit", 
       datatype: "json", 
       //data: mydata, 
       width:1000, 
       //jsonReader: { 
       //    repeatitems : false, 
       //   }, 
       colNames: ["","Id","Uid","Custom Id","Image Name","Coord. X","Coord. Y","Gender","Progress","Status","Created","Updated"], 
       colModel: [{"name":"act","template":"actions","formatoptions":{"editformbutton":true}},{"name":"id","align":"center","width":33,"editable":false,"hidden":true},{"name":"uid","align":"center","width":33,"editable":true,"hidden":true,"editrules":{"edithidden":false,"required":false}},{"name":"ta_id","align":"center","width":100,"editrules":{"required":true}},{"name":"image","width":150,"template":"text","editrules":{"required":true}},{"name":"x","width":100,"align":"center","template":"integer","editrules":{"required":true}},{"name":"y","width":100,"align":"center","template":"integer","editrules":{"required":true}},{"name":"gender","width":100,"align":"center","formatter":"select","stype":"select","editrules":{"required":true},"edittype":"select","editoptions":{"value":"f:Female;m:Male","defaultValue":"m"},"searchoptions":{"sopt":["eq","ne"],"value":":Any;f:Female;m:Male"}},{"name":"progress","width":120,"align":"center","formatter":"select","stype":"select","editrules":{"required":true},"editable":false,"edittype":"select","editoptions":{"value":"-:New;pf:Process Failed;ps:Process Scheduled;pss:Process Success;p:Processing...;s:Staging;tf:Test Failed;ts:Test Scheduled;tss:Test Success;t:Testing...","defaultValue":"m"},"searchoptions":{"sopt":["eq","ne"],"value":":Any;-:New;pf:Process Failed;ps:Process Scheduled;pss:Process Success;p:Processing...;s:Staging;tf:Test Failed;ts:Test Scheduled;tss:Test Success;t:Testing..."}},{"name":"status","width":100,"align":"center","formatter":"select","stype":"select","edittype":"select","editoptions":{"value":"a:Active;n:New","defaultValue":"m"},"searchoptions":{"sopt":["eq","ne"],"value":":Any;a:Active;n:New"}},{"name":"date_created","width":150,"template":"text","editable":false},{"name":"last_updated","width":150,"template":"text","editable":false}] 

這裏是我從我的服務器（DB）按jqGrid的規範實際數據：

{"page":1,"total":1,"records":7,"rows":[{"id":32,"cell":[32,"889daf31ff3e49544f52850258439600","2uu","2ok",2,2,"m","-","a","2017-02-10 18:57:05","2017-02-10 23:37:12"]},{"id":30,"cell":[30,"","11","11",1,1,"m","-","a","2017-02-10 18:01:52","2017-02-10 18:01:52"]},{"id":29,"cell":[29,"aaa","ww222111uu","11",1,1,"m","-","a","2017-02-10 18:00:36","2017-02-10 23:37:08"]},{"id":27,"cell":[27,"","11","1",1,1,"m","-","a","2017-02-10 17:57:41","2017-02-10 17:57:41"]},{"id":25,"cell":[25,"","4tt","4img",4,4,"f","-","n","2017-02-10 17:50:21","2017-02-11 00:26:03"]},{"id":24,"cell":[24,"","1","1",1,1,"m","-","a","2017-02-10 17:49:38","2017-02-10 17:49:38"]},{"id":22,"cell":[22,"","bbb","imam 222",2,22,"f","p","n","2017-02-08 20:14:55","2017-02-10 13:27:57"]}]} 

正如你可以看到單元行具有比colNames和colModel少列。還id和uid列被隱藏。我說從DB額外的假柱，但它並沒有幫助

我使用的jqGrid 4.13.7預

Answer 1

我建議你返回對象，如

{ 
    "id": 32, 
    "uid": "889daf31ff3e49544f52850258439600", 
    "ta_id": "2uu", 
    "image": "2ok", 
    "x": 2, 
    "y": 2, 
    "gender": "m", 
    "progress": "-", 
    "status": "a", 
    "date_created": "2017-02-10 18:57:05", 
    "last_updated": "2017-02-10 23:37:12" 
} 

，而不是

{ 
    "id": 32, 
    "cell": [ 
     32, "889daf31ff3e49544f52850258439600", "2uu", "2ok", 2, 2, "m", "-", "a", 
     "2017-02-10 18:57:05", "2017-02-10 23:37:12" 
    ] 
} 

作爲服務器響應。它會簡化你的代碼。

如果你需要處理的數據的當前格式，那麼你將不得不使用強制repeatitems: false模式的選項

jsonReader: { 
    repeatitems: false 
} 

和使用的colModeljsonmap財產從哪個元素通知的jqGrid項目一應該讀取列數據。該jsonmap可無論是在字符串形式類似

jsonmap: "cell.1" 

或函數形式：

jsonmap: function (item) { 
    return item.cell[1]; 
} 

爲了使代碼更易於維護，你可以這樣定義

var columnOrder = { 
     id: 0, 
     uid: 1, 
     ta_id: 2, 
     image: 3, 
     x: 4, 
     y: 5, 
     gender: 6, 
     progress: 7, 
     status: 8, 
     date_created: 9, 
     last_updated: 10 
    }; 

的對象，按列名提供cell數組中的索引並使用jsonmap，如

jsonmap: function (item) { 
    return item.cell[columnOrder.uid]; 
} 

演示https://jsfiddle.net/OlegKi/ozzgnaeh/2/演示了這種方法。