我不得不讓這個代碼運行一個骰子游戲,這是我的第一個遊戲程序,我遇到了一些錯誤I以前從未見過,所以我盡了最大的努力來解決它們。所以我留下的唯一錯誤是這些:編寫if語句時出錯''=':左操作數必須是l值'
'=' : left operand must be l-value
爲最後三個if語句。我知道這可能只是我的問題的開始,但我對這一切都很陌生,所以任何建議都非常感謝。
#include <iostream>
#include <ctime> //Include Header file for time functions
#include <cstdlib> //Include Header file for random number generators
#include "graph1.h"
using namespace std;
int main()
{
//Variable Declaration
int rv1 = 0; //Random number for the 1st dice
int rv2 = 0; //Random number for the 2nd dice
int seed=0;
int wager=0;
//Display graphics
displayGraphics();
cout<< "Wager";
cin>>wager;
//Initialize random number generator
srand(time(0));
//Generate two random numbers between 1 and 6 inclusive
rv1 = (rand()%6)+1; /* Function rand() generate a random number,
(rand()%6+1) generate a random number between 1&6 */
rv2 = (rand()%6)+1;
//rv1
if(rv1=1)
{cout<<displayBMP("1.bmp",200,150);}
else
{ if (rv1=2)
cout<<displayBMP("2.bmp",200,150);}
if (rv1=3)
{cout<<displayBMP("3.bmp",200,150);}
if (rv1=4)
{cout<<displayBMP("4.bmp",200,150);}
if (rv1=5)
{cout<<displayBMP("5.bmp",200,150);}
if (rv1=6)
{cout<<displayBMP("6.bmp",200,150);}
//rv2
if(rv2=1)
{cout<<displayBMP("1.bmp",200,250);}
if (rv2=2)
{cout<<displayBMP("2.bmp",200,250);}
if (rv2=3)
{cout<<displayBMP("3.bmp",200,250);}
if (rv2=4)
{cout<<displayBMP("4.bmp",200,250);}
if (rv2=5)
{cout<<displayBMP("5.bmp",200,250);}
if (rv2=6)
{cout<<displayBMP("6.bmp",200,250);}
if (wager<5)
{
cout<<displayBMP("smiley.bmp",250,100);
gout<<setPos(150,280)<<"Your wager of"<<wager<<"is less than required $5/";
gout<<setPos(150,295)<<"Please re-run program and enter larger amount!/n";
return-1;
}
if (((rv1+rv2)%2)=0)
{ gout<<setPos(200,280)<<"Dice total"<<(rv1+rv2)<<endg;
cout<<"You win $2 extra for even roll!/n";
cout<<"Your winnings:$2+Original Wager:$"<<wager<<"=$"<<wager+2<<endg;
}
if(rv1+rv2=7)
{gout<<setPos(200,280)<<"Dice total"<<(rv1+rv2)<<endg;
cout<<"Youre lucky today!/n";
cout<<"You double your wager/n";
cout<<"Your winnings:$10+Original Wager=$"<<wager<<"=$"<<wager*2<<endg;
}
if(((rv1+rv2)%2)=1)
{gout<<setPos(200,280)<<"Dice total"<<(rv1+rv2)<<endg;
cout<<"You lose $2 for odd roll!/n";
cout<<"Original Wager:$"<<wager<<"Losses:$2=$"<<wager-2<<endg;
}
return 0;
}
@Creris跳入和編輯怎麼樣?在你的代表階段,你甚至可以獲得額外的代表來解決這個問題。 – 2014-10-20 18:02:01
我想我可以。並且meh代表是rep,名字旁邊的數字 – Creris 2014-10-20 18:04:42
@Creris那麼,建設性也是一種態度。請閉嘴,否則請! – 2014-10-20 18:27:06