顯示保齡球得分最高的平均值

Question

我無法讓代碼顯示四條平均值中最高的平均值，我似乎只得到最後的平均得分，並且填補了它不是最高的平均值得分了。

這裏是我的代碼：

​​3210

下面是代碼的運行示例：

Player 1 

Enter your bowling score: 

300 

Enter your bowling score: 

222 

Enter your bowling score: 

-1 

Average= 261.00 

Player 2 

Enter your bowling score: 

210 

Enter your bowling score: 

211 

Enter your bowling score: 

300 

Enter your bowling score: 

-1 

Average= 240.00 

Player 3 

Enter your bowling score: 

233 

Enter your bowling score: 

-1 

Average= 233.00 

Player 4 
Enter your bowling score: 

112 

Enter your bowling score: 

-1 

Average= 112.00 

Highest average:112.0 // this is not the highest score. 

Answer 1

if (avg > highest_average) {   
    highest_average= avg; 

此代碼應該是在你的for循環，否則最高平均永遠不會被更新。

Answer 2

你永遠不更新最高平均每個玩家，只爲最後的球員。這就是爲什麼你總是使用最後一個人的平均值。

只需在for循環中移動if語句，它應該可以正常工作。確保在循環之外留下您的打印語句，以便您最後只打印一次最高平均值。

for (int i = 1; i <= players; i++) { 
    System.out.println("Player " + i); 
    do { 
     System.out.println("Enter your bowling score:"); 
     G = keyboard.nextInt(); 
     scores += G; 
     times++; 
    } while ((G != -1)); // -1 is what makes the loop end for the current player, a total of four players will get an average after -1 is inputted 

    scores += +1; 
    times = times - 1; 
    avg = (scores)/(times); 
    System.out.printf("Average= %.2f\n", avg); 
    scores = 0; 
    times = 0; 
    System.out.println(""); 

    if (avg > highest_average) { 
     highest_average = avg; 
    } 
} 
System.out.println("Highest average:" + highest_average);