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我工作的這個功課是有點困惑我......Java的通用二叉搜索樹類型的問題
我提供了以下BinarySearchTree類
import java.util.NoSuchElementException;
/**
*
* @param <T> The type of data stored in the nodes of the tree, must implement Comparable<T> with the compareTo method.
*/
public class BinarySearchTree<T extends Comparable<T>> {
BinaryTree<T> tree;
int size;
public BinarySearchTree() {
tree = new BinaryTree<T>();
size = 0;
}
public boolean isEmpty() {
return tree.isEmpty();
}
protected BinaryTree<T> recursiveSearch(BinaryTree<T> root, T key) {
if (root == null) {
return null;
}
int c = key.compareTo(root.data);
if (c == 0) {
return root;
}
if (c < 0) {
return recursiveSearch(root.left, key);
} else {
return recursiveSearch(root.right, key);
}
}
public T search(T key) {
if (tree.isEmpty()) {
return null;
}
return recursiveSearch(tree, key).data;
}
public void insert(T item) {
if (tree.isEmpty()) { // insert here
tree.makeRoot(item);
size++;
return;
}
// do an iterative descent
BinaryTree<T> root = tree;
boolean done=false;
BinaryTree<T> newNode = null;
while (!done) {
int c = item.compareTo(root.data);
if (c == 0) { // duplicate found, cannot be inserted
throw new OrderViolationException();
}
if (c < 0) { // insert in left subtree
if (root.left == null) { // insert here as left child
newNode = new BinaryTree<T>();
root.left = newNode;
done=true;
} else { // go further down left subtree
root = root.left;
}
} else { // insert in right subtree
if (root.right == null) { // insert here as right child
newNode = new BinaryTree<T>();
root.right = newNode;
done=true;
} else { // go further down right subtree
root = root.right;
}
}
}
// set fields of new node
newNode.data = item;
newNode.parent = root;
size++;
}
/**
* @param deleteNode Node whose parent will receive new node as right or left child,
* depending on whether this node is its parent's right or left child.
* @param attach The node to be attached to parent of deleteNode.
*/
protected void deleteHere(BinaryTree<T> deleteNode, BinaryTree<T> attach) {
// deleteNode has only one subtree, attach
BinaryTree<T> parent = deleteNode.parent;
deleteNode.clear(); // clear the fields
if (parent == null) {
return;
}
if (deleteNode == parent.left) {
// left child of parent, attach as left subtree
parent.detachLeft();
parent.attachLeft(attach);
return;
}
// attach as right subtree
parent.detachRight();
parent.attachRight(attach);
}
protected BinaryTree<T> findPredecessor(BinaryTree<T> node) {
if (node.left == null) {
return null;
}
BinaryTree<T> pred = node.left; // turn left once
while (pred.right != null) { // keep turning right
pred = pred.right;
}
return pred;
}
public T delete(T key) {
if (tree.isEmpty()) { // can't delete from an empty tree
throw new NoSuchElementException();
}
// find node containing key
BinaryTree<T> deleteNode = recursiveSearch(tree, key);
if (deleteNode == null) { // data not found, can't delete
throw new NoSuchElementException();
}
BinaryTree<T> hold;
// case c: deleteNode has exactly two subtrees
if (deleteNode.right != null && deleteNode.left != null) {
hold = findPredecessor(deleteNode);
deleteNode.data = hold.data;
deleteNode = hold; // fall through to case a or b
}
// case a: deleteNode is a leaf
if (deleteNode.left == null && deleteNode.right == null) {
deleteHere(deleteNode, null);
size--;
return deleteNode.data;
}
// case b: deleteNode has exactly one subtree
if (deleteNode.right != null) {
hold = deleteNode.right;
deleteNode.right = null;
} else {
hold = deleteNode.left;
deleteNode.left = null;
}
deleteHere(deleteNode,hold);
if (tree == deleteNode) { // root deleted
tree = hold;
}
size--;
return deleteNode.data;
}
public T minKey() {
if (tree.data == null) { // tree empty, can't find min value
throw new NoSuchElementException();
}
BinaryTree<T> root = tree;
T min=root.data;
root = root.left; // turn left once
while (root != null) { // keep going left to leftmost node
min = root.data;
root = root.left;
}
return min;
}
public T maxKey() {
if (tree.getData() == null) { // tree empty, can't find max value
throw new NoSuchElementException();
}
BinaryTree<T> root=tree;
T max=root.data;
root = root.right; // turn right once
while (root != null) { // keep going to rightmost node
max = root.data;
root = root.right;
}
return max;
}
public int size() {
return size;
}
protected void recursivePreOrder(BinaryTree<T> root, Visitor<T> visitor) {
if (root != null) {
visitor.visit(root);
recursivePreOrder(root.left, visitor);
recursivePreOrder(root.right, visitor);
}
}
public void preOrder(Visitor<T> visitor) {
if (tree.isEmpty()) {
return;
}
recursivePreOrder(tree, visitor);
}
protected void recursiveInOrder(BinaryTree<T> root, Visitor<T> visitor) {
if (root != null) {
recursiveInOrder(root.left, visitor);
visitor.visit(root);
recursiveInOrder(root.right, visitor);
}
}
public void inOrder(Visitor<T> visitor) {
if (tree.isEmpty()) {
return;
}
recursiveInOrder(tree, visitor);
}
protected void recursivePostOrder(BinaryTree<T> root, Visitor<T> visitor) {
if (root != null) {
recursivePostOrder(root.left, visitor);
recursivePostOrder(root.right, visitor);
visitor.visit(root);
}
}
public void postOrder(Visitor<T> visitor) {
if (tree.isEmpty()) {
return;
}
recursivePostOrder(tree, visitor);
}
}
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現在我有另一班學生.... 我想創建一個Student對象的二叉查找樹..
BinarySearchTree<Student> tree = new BinarySearchTree<Student>();
然而，當我這樣做，我得到以下錯誤：
約束不匹配：類型學生是不是有界參數類型的有效替代品> BinarySearchTree
任何想法，這裏發生了什麼。 ..我無法弄清楚。
通過我建議必將是「BinarySearchTree>「而不是」BinarySearchTree >「。你擁有它的方式比它需要的更具限制性，當你有實現Comparable的類的子類時會遇到問題。 –
newacct
2009-05-02 05:59:29